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How do I tidy up an HTML file's indentation in VI?

...gia8W2 . The file is called home.html. I don't have any problem to indent .php files. Here you have my .vimrc: pastebin.com/FAJ0MCA9 – ziiweb Apr 24 '13 at 18:24 ...
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Git: “please tell me who you are” error

... I spend on it lots hours when i call php script to init and commit git. And i Found the work flow should Be: 1.git init 2.git config user.name "someone" 3.git config user.email "someone@someplace.com" 4.git add * 5.git commit -m "some init msg" If you swap [2...
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Store print_r result into a variable as a string or text

... Not the answer you're looking for? Browse other questions tagged php or ask your own question.
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Stop form refreshing page on submit

... $.ajax({ type: 'post', url: 'myPageName.php', data: $('#myFormName').serialize(), success: function () { alert("Email has been sent!"); } }); e.preventDefault(); }); })...
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AJAX post error : Refused to set unsafe header “Connection”

I have the following custom ajax function that posts data back to a PHP file. Everytime the post of data happens I get the following two errors : ...
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Insert text into textarea with jQuery

... How about if the result is coming from a PHP page and handled by jQuery? (in between data is transmitted using Json) – Abu Rayane Apr 1 '16 at 6:31 ...
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How to print without newline or space?

... a conversion to a tuple). I expect these sorts of shoddy constructs from PHP, not Python. So it's best to not ever use this. – Eric Leschinski Jul 26 '15 at 16:48 ...
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Parsing query strings on Android

... import org.eclipse.jetty.util.*; URL url = new URL("www.example.com/index.php?foo=bar&bla=blub"); MultiMap<String> params = new MultiMap<String>(); UrlEncoded.decodeTo(url.getQuery(), params, "UTF-8"); assert params.getString("foo").equals("bar"); assert params.getString("bla").equ...
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Git Diff with Beyond Compare

... I also found this article: scootersoftware.com/support.php?zz=kb_vcs – Guy Avraham Nov 5 '16 at 9:29 ...
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How to get distinct values from an array of objects in JavaScript?

... If this were PHP I'd build an array with the keys and take array_keys at the end, but JS has no such luxury. Instead, try this: var flags = [], output = [], l = array.length, i; for( i=0; i<l; i++) { if( flags[array[i].age]) conti...