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Ruby regular expression using variable na<em>mem>e

...ular expression pattern in ruby that is based on the value of a variable na<em>mem>e? 5 Answers ...
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How do I convert a byte array to Base64 in Java?

...).decode(encoded.getBytes())); println(decoded) // Outputs "Hello" For <em>mem>ore info, see Base64. Java &a<em>mem>p;lt; 8 Base64 is not bundled with Java versions less than 8. I reco<em>mem><em>mem>end using Apache Co<em>mem><em>mem>ons Codec. For direct byte arrays: Base64 codec = new Base64(); byte[] encoded = codec.encode("Hello".getBy...
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Should I use docu<em>mem>ent.createDocu<em>mem>entFrag<em>mem>ent or docu<em>mem>ent.createEle<em>mem>ent

I was reading about docu<em>mem>ent frag<em>mem>ents and DO<em>Mem> reflow and wondered how docu<em>mem>ent.createDocu<em>mem>entFrag<em>mem>ent differed fro<em>mem> docu<em>mem>ent.createEle<em>mem>ent as it looks like neither of the<em>mem> exist in the DO<em>Mem> until I append the<em>mem> to a DO<em>Mem> ele<em>mem>ent. ...
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Calculating how <em>mem>any <em>mem>inutes there are between two ti<em>mem>es

I have a datagridview in <em>mem>y application which holds start and finish ti<em>mem>es. I want to calculate the nu<em>mem>ber of <em>mem>inutes between these two ti<em>mem>es. So far I have got: ...
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In Subli<em>mem>e Text 2, how do I open new files in a new tab?

When I'<em>mem> editing with files on the server, and I click to edit the<em>mem>, if I'<em>mem> editing <em>mem>ultiple files (say an HT<em>Mem>L file and a CSS file) but they open in new windows, which, on <em>mem>y s<em>mem>all laptop display is a little inconvenient. ...
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Sass .scss: Nesting and <em>mem>ultiple classes?

I'<em>mem> using Sass (.scss) for <em>mem>y current project. 3 Answers 3 ...
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How to get first record in each group using Linq

... var res = fro<em>mem> ele<em>mem>ent in list group ele<em>mem>ent by ele<em>mem>ent.F1 into groups select groups.OrderBy(p =&a<em>mem>p;gt; p.F2).First(); ...
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How can I divide two integers to get a double?

... You want to cast the nu<em>mem>bers: double nu<em>mem>3 = (double)nu<em>mem>1/(double)nu<em>mem>2; Note: If any of the argu<em>mem>ents in C# is a double, a double divide is used which results in a double. So, the following would work too: double nu<em>mem>3 = (double)nu<em>mem>1/nu<em>mem>2; For ...
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How do I tell <em>mem>atplotlib that I a<em>mem> done with a plot?

... You can use figure to create a new plot, for exa<em>mem>ple, or use close after the first plot. share | i<em>mem>prove this answer | follow | ...
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C# - Selectively suppress custo<em>mem> Obsolete warnings

I'<em>mem> using the Obsolete attribute (as just suggested by fellow progra<em>mem><em>mem>ers) to show a warning if a certain <em>mem>ethod is used. ...