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numpy: most efficient frequency counts for unique values in an array
...ncount(x)
ii = np.nonzero(y)[0]
And then:
zip(ii,y[ii])
# [(1, 5), (2, 3), (5, 1), (25, 1)]
or:
np.vstack((ii,y[ii])).T
# array([[ 1, 5],
[ 2, 3],
[ 5, 1],
[25, 1]])
or however you want to combine the counts and the unique values.
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3 Answers
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Booleans, conditional operators and autoboxing
...nd operand to boolean)
E2: `true ? null : false` - Boolean (autoboxing of 3rd operand to Boolean)
See Java Language Specification, section 15.25 Conditional Operator ? :
For E1, the types of the 2nd and 3rd operands are Boolean and boolean respectively, so this clause applies:
If one of the...
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310
In macOS 10.9+ & iOS 8+, there's a method on NSCalendar/Calendar that does exactly this!
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355
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Eliahu Aaron
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answered Sep 14 '10 at 21:38
Max GalkinMax Ga...
