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What is the most efficient way to store a list in the Django models?
Currently I have a lot of python objects in my code similar to the following:
12 Answers
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How to count the frequency of the elements in an unordered list?
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The python groupby creates new groups when the value it sees changes. In this case 1,1,1,2,1,1,1] would return [3,1,3]. If you expected [6,1] then just be sure to sort the data before using groupby.
– Evan
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Reading specific lines only
... 29:
break
fp.close()
Note that i == n-1 for the nth line.
In Python 2.6 or later:
with open("file") as fp:
for i, line in enumerate(fp):
if i == 25:
# 26th line
elif i == 29:
# 30th line
elif i > 29:
break
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Python: access class property from string [duplicate]
I have a class like the following:
4 Answers
4
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Convert all strings in a list to int
In Python, I want to convert all strings in a list to integers.
4 Answers
4
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Delete a dictionary item if the key exists [duplicate]
... This is called the eaiser to ask for forgiveness than permission (EAFP) Python style.
– akki
Jul 22 '16 at 16:55
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org.apache.tomcat.util.modeler.ManagedBean tomcat启动不了 - Python - 清泛IT社区，为创新赋能！
java版本太低了，下载新版本java：
http://www.oracle.com/technetwork/java/javase/downloads/jdk6-jsp-136632.html
JAVA“无法启动该应用程序”的解决办法 - Python - 清泛IT社区，为创新赋能！
调用虚拟控制台时出现了如下的错误，“无法启动该应用程序”，如下：
是因为JAVA的安全设置问题，进入C:Program Files (x86)Javajre7in，打开javacpl.exe，将安全级别设置为“中”即可。