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LINQ Single vs First
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If you're expecting a Single record, it's always good to be explicit in your code.
I know others have written why you use one or the other, but I thought I'd illustrate why you should NOT use one, when you mean the other.
Note: In my code, I will typically use F...
PhoneGap: Detect if running on desktop browser
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edited May 23 '17 at 12:18
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answered May 12 '12 at ...
How to run Gulp tasks sequentially one after the other
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It's not an official release yet, but the coming up Gulp 4.0 lets you easily do synchronous tasks with gulp.series. You can simply do it like this:
gulp.task('develop', gulp.series('clean', 'coffee'))
I found a good blog p...
What does jquery $ actually return?
...o what you should pass the function, I don't see any information on what it actually returns .
9 Answers
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What is the yield keyword used for in C#?
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The yield keyword actually does quite a lot here.
The function returns an object that implements the IEnumerable<object> interface. If a calling function starts foreaching over this object, the function is called again until it "yields". This is syntac...
How to auto-indent code in the Atom editor?
How do you auto-indent your code in the Atom editor? In other editors you can usually select some code and auto-indent it.
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How do I create a new Swift project without using Storyboards?
...vigationController?
Swift classes require non-optional properties to be initialized during the instantiation:
Classes and structures must set all of their stored properties to an appropriate initial value by the time an instance of that class or structure is created. Stored properties cannot be le...
How can I reconcile detached HEAD with master/origin?
I'm new at the branching complexities of Git. I always work on a single branch and commit changes and then periodically push to my remote origin.
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What does map(&:name) mean in Ruby?
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It's shorthand for tags.map(&:name.to_proc).join(' ')
If foo is an object with a to_proc method, then you can pass it to a method as &foo, which will call foo.to_proc and use that as the method's block.
The Symbol#t...
Any idea why I need to cast an integer literal to (int) here?
...tract 128 from (Integer) instead of casting -128 to Integer. Add () to fix it
Integer i3 = (Integer) -128; // doesn't compile
Integer i3 = (Integer) (-128); // compiles
According to BoltClock in the comments the cast to int works as intended, because it is a reserved word and therefore can't be ...