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LINQ with groupby and count
... .OrderBy(x => x.Metric))
{
Console.WriteLine("{0} {1}", line.Metric, line.Count);
}
> This was a brilliantly quick reply but I'm having a bit of an issue with the first line, specifically "data.groupby(info=>info.metric)"
I'm assuming you already have a list/array...
How to swap two variables in JavaScript
...swap the values of two variables.
Given variables a and b:
b = [a, a = b][0];
Demonstration below:
var a=1,
b=2,
output=document.getElementById('output');
output.innerHTML="<p>Original: "+a+", "+b+"</p>";
b = [a, a = b][0];
output.innerHTML+="<p>Swapped: ...
Print all day-dates between two dates [duplicate]
...
I came up with this:
from datetime import date, timedelta
sdate = date(2008, 8, 15) # start date
edate = date(2008, 9, 15) # end date
delta = edate - sdate # as timedelta
for i in range(delta.days + 1):
day = sdate + timedelta(days=i)
print(day)
The output:
2008-08-15
2008-...
How do I break out of nested loops in Java?
...ic static void main(String[] args) {
outerloop:
for (int i=0; i < 5; i++) {
for (int j=0; j < 5; j++) {
if (i * j > 6) {
System.out.println("Breaking");
break outerloop;
}
Sys...
Associativity of “in” in Python?
... return 1 in [] in 'a'
.....:
In [122]: dis.dis(func)
2 0 LOAD_CONST 1 (1)
3 BUILD_LIST 0
6 DUP_TOP
7 ROT_THREE
8 COMPARE_OP 6 (in)
11 JUMP_IF_FAL...
JavaScript get element by name
...
250
The reason you're seeing that error is because document.getElementsByName returns a NodeList of ...
How to append contents of multiple files into one file
...
10 Answers
10
Active
...
GraphViz - How to connect subgraphs?
...ue statement is required.
digraph G {
compound=true;
subgraph cluster0 {
a -> b;
a -> c;
b -> d;
c -> d;
}
subgraph cluster1 {
e -> g;
e -> f;
}
b -> f [lhead=cluster1];
d -> e;
c -> g [ltail=cluster0,lhead=cluster1];
c -> e [...
How to compare times in Python?
...datetime.datetime.now()
>>> today8am = now.replace(hour=8, minute=0, second=0, microsecond=0)
>>> now < today8am
True
>>> now == today8am
False
>>> now > today8am
False
share
...
Moving average or running mean
... works great.
mylist = [1, 2, 3, 4, 5, 6, 7]
N = 3
cumsum, moving_aves = [0], []
for i, x in enumerate(mylist, 1):
cumsum.append(cumsum[i-1] + x)
if i>=N:
moving_ave = (cumsum[i] - cumsum[i-N])/N
#can do stuff with moving_ave here
moving_aves.append(moving_ave)
...