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Why use ICollection and not IEnumerable or List on many-many/one-many relationships?
...ary/92t2ye13.aspx) for a list of objects that needs to be iterated through and modified, List<> for a list of objects that needs to be iterated through, modified, sorted, etc (See here for a full list: http://msdn.microsoft.com/en-us/library/6sh2ey19.aspx).
From a more specific standpoint, la...
Pointers in C: when to use the ampersand and the asterisk?
I'm just starting out with pointers, and I'm slightly confused. I know & means the address of a variable and that * can be used in front of a pointer variable to get the value of the object that is pointed to by the pointer. But things work differently when you're working with arrays, string...
LINQ Select Distinct with Anonymous Types
...
Have a read through K. Scott Allen's excellent post here:
And Equality for All ... Anonymous Types
The short answer (and I quote):
Turns out the C# compiler overrides
Equals and GetHashCode for anonymous
types. The implementation of the two
overridden methods uses all the...
%d,%c,%s,%x等转换符 释义 - C/C++ - 清泛IT论坛，有思想、有深度
转换说明符
%a(%A) 浮点数、十六进制数字和p-(P-)记数法(C99)
%c 字符
%d 有符号十进制整数
%f 浮点数(包括float和doulbe)
%e(%E) 浮点数指数输出[e-(E-)记数法]
%g(%G) 浮点...
shared_ptr指针被赋值后，原指针会引用清零、自动释放。 - C/C++ - 清泛IT...
shared_ptr指针被赋值后，原指针会引用清零、自动释放。
std::shared_ptr<int> intg;
void foo(std::shared_ptr<int> p)
{
        intg = p;   // 原指针释放，存储新的智能指针
        //*(in...
PostgreSQL “DESCRIBE TABLE”
... equivalent of Oracle's DESCRIBE TABLE in PostgreSQL (using the psql command)?
22 Answers
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LEFT OUTER JOIN in LINQ
...ay to do that with where clause?
Correct problem:
For inner join is easy and I have a solution like this
22 Answers
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HTML: Include, or exclude, optional closing tags?
...unless I have a very good reason not to) because it lends to more readable and updateable code.
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What is the logic behind the “using” keyword in C++?
...aration. The
identifier following the using keyword becomes a typedef-name and the
optional attribute-specifier-seq following the identifier appertains
to that typedef-name. It has the same semantics as if it were
introduced by the typedef specifier. In particular, it does not define
a new type and ...
Move capture in lambda
...ref( T && x )
{
return rref_impl<T>{ std::move(x) };
}
And here's a test case for that function that ran successfully on my gcc 4.7.3.
int main()
{
std::unique_ptr<int> p{new int(0)};
auto rref = make_rref( std::move(p) );
auto lambda =
[rref]() mutabl...