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Mockito : how to verify method was called on an object created within a method?
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Dependency Injection
If you inject the Bar instance, or a factory that is used for creating the Bar instance (or one of the other 483 ways of doing this), you'd have the access necessary to do perform the test.
Factory Example:
Given a Foo class written like thi...
Get a list of all git commits, including the 'lost' ones
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Not particularly easily- if you've lost the pointer to the tip of a branch, it's rather like finding a needle in a haystack. You can find all the commits that don't appear to be referenced any more- git fsck --unreachable will do this for you- but that will include commits that you threw away...
Why should casting be avoided? [closed]
I generally avoid casting types as much as possible since I am under the impression that it's poor coding practice and may incur a performance penalty.
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Cross-Domain Cookies
I have two webapps WebApp1 and WebApp2 in two different domains.
14 Answers
14
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builtins.TypeError: must be str, not bytes
I've converted my scripts from Python 2.7 to 3.2, and I have a bug.
2 Answers
2
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How to run multiple DOS commands in parallel?
...nd prompt and allow you to run multiple commands at the same time from one batch file.
Hope this helps!
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How do I escape spaces in path for scp copy in Linux?
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Basically you need to escape it twice, because it's escaped locally and then on the remote end.
There are a couple of options you can do (in bash):
scp user@example.com:"'web/tmp/Master File 18 10 13.xls'" .
scp user@exampl...
Basic HTTP authentication with Node and Express 4
It looks like implementing basic HTTP authentication with Express v3 was trivial:
9 Answers
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Checking images for similarity with OpenCV
Does OpenCV support the comparison of two images, returning some value (maybe a percentage) that indicates how similar these images are? E.g. 100% would be returned if the same image was passed twice, 0% would be returned if the images were totally different.
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Numpy first occurrence of value greater than existing value
...]: aa = np.arange(-N,N)
In [4]: timeit np.argmax(aa>N/2)
100000 loops, best of 3: 52.3 us per loop
In [5]: timeit np.where(aa>N/2)[0][0]
10000 loops, best of 3: 141 us per loop
In [6]: timeit np.nonzero(aa>N/2)[0][0]
10000 loops, best of 3: 142 us per loop
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