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Random number generator only generating one random number
..., max);
}
}
Edit (see comments): why do we need a lock here?
Basically, Next is going to change the internal state of the Random instance. If we do that at the same time from multiple threads, you could argue "we've just made the outcome even more random", but what we are actually doing is ...
Android: Getting a file URI from a content URI?
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Actually, I just re-read the docs for getContentResolver().openInputStream(), and it works automatically for schemes of "content" or "file", so you don't need to check the scheme... if you can safely assume that it's always going...
`if __name__ == '__main__'` equivalent in Ruby
...f there isn't really a good, clean way of doing this.
EDIT: Found it.
if __FILE__ == $0
foo()
bar()
end
But it's definitely not common.
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How to get the caller's method name in the called method?
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This seems to work just fine:
import sys
print sys._getframe().f_back.f_code.co_name
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What is the use for Task.FromResult in C#
In C# and TPL ( Task Parallel Library ), the Task class represents an ongoing work that produces a value of type T.
6 Ans...
Is there an equivalent to CTRL+C in IPython Notebook in Firefox to break cells that are running?
...errupt the entire iPython Notebook server. This will stop iPython Notebook alltogether, which means it won't be possible to restart or save your work, so this is obviously not a great solution (you need to hit CTRL+C twice because it's a safety feature so that people don't do it by accident). In cas...
Circular gradient in android
...olling, you're right that the android:gradientRadius="250" doesn't work at all, I guess it behaved differently on older Android versions.
– Justin
Apr 22 '15 at 14:58
add a co...
Forward declaring an enum in C++
...can't know the storage required for the enum variable. C++ Compiler's are allowed to specify the actual storage space based on the size necessary to contain all the values specified. If all that is visible is the forward declaration, the translation unit can't know what storage size will have been...
How to get the concrete class name as a string? [duplicate]
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instance.__class__.__name__
example:
>>> class A():
pass
>>> a = A()
>>> a.__class__.__name__
'A'
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Unmangling the result of std::type_info::name
... calling function. This should be relatively easy, standard C++ has a type_info class. This contains the name of the typeid'd class/function/etc. but it's mangled. It's not very useful. I.e. typeid(std::vector<int>).name() returns St6vectorIiSaIiEE .
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