大约有 44,600 项符合查询结果（耗时：0.0360秒） [XML]
How to run a command in the background and get no output?
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227
Use nohup if your background job takes a long time to finish or you just use SecureCRT or some...
Best way to do multi-row insert in Oracle?
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answered Sep 2 '08 at 14:08
EspoEspo
38.7k2020 gold badges126126 silver badges156156 bronze badges
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Checking for the correct number of arguments
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218
#!/bin/sh
if [ "$#" -ne 1 ] || ! [ -d "$1" ]; then
echo "Usage: $0 DIRECTORY" >&2
e...
How do I convert from BLOB to TEXT in MySQL?
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266
That's unnecessary. Just use SELECT CONVERT(column USING utf8) FROM..... instead of just SELEC...
Add Keypair to existing EC2 instance
I was given AWS Console access to an account with 2 instances running that I cannot shut down (in production). I would however like to gain SSH access to these instances, is it possible to create a new Keypair and apply it to the instances so I can SSH in? Obtaining the exisiting pem file for the ke...
Iterating over dictionaries using 'for' loops
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5552
key is just a variable name.
for key in d:
will simply loop over the keys in the dictionary...
How to fix Error: “Could not find schema information for the attribute/element” by creating schema
I have a windows forms application written in VS2010 with C# and get the following errors in the app.config file:
10 Answ...
SQL Logic Operator Precedence: And and Or
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296
And has precedence over Or, so, even if a <=> a1 Or a2
Where a And b
is not the same...
Replace specific characters within strings
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With a regular expression and the function gsub():
group <- c("12357e", "12575e", "197e18", "e18947")
group
[1] "12357e" "12575e" "197e18" "e18947"
gsub("e", "", group)
[1] "12357" "12575" "19718" "18947"
What gsub does here is to replace each occurrence of "e" with an empty string ""....
Swift: Pass array by reference?
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edited Nov 15 '17 at 21:23
iwasrobbed
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