大约有 43,100 项符合查询结果（耗时：0.0412秒） [XML]
Image Greyscale with CSS & re-color on mouse-over?
... 0.3333 0.3333 0 0 0.3333 0.3333 0.3333 0 0 0.3333 0.3333 0.3333 0 0 0 0 0 1 0\'/></filter></svg>#grayscale"); /* Firefox 3.5+ */
filter: gray; /* IE6-9 */
-webkit-filter: grayscale(100%); /* Chrome 19+ & Safari 6+ */
}
img.grayscale:hover {
filter: none;
-webkit-filter: ...
urllib2.HTTPError: HTTP Error 403: Forbidden
...
171
By adding a few more headers I was able to get the data:
import urllib2,cookielib
site= "htt...
Ruby ampersand colon shortcut [duplicate]
...foo }
something(&:foo)
Also, to_proc on Symbol is implemented in Ruby 1.8.7 and 1.9, so it is in fact a "ruby thing".
So, to sum up: & calls to_proc on the object and passes it as a block to the method, and Ruby implements to_proc on Symbol.
...
Replace X-axis with own values
...
179
Not sure if it's what you mean, but you can do this:
plot(1:10, xaxt = "n", xlab='Some Letter...
Remove border from buttons
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188
Add
padding: 0;
border: none;
background: none;
to your buttons.
Demo:
https://jsfiddle.n...
Get first and last date of current month with JavaScript or jQuery [duplicate]
...= new Date();
var firstDay = new Date(date.getFullYear(), date.getMonth(), 1);
var lastDay = new Date(date.getFullYear(), date.getMonth() + 1, 0);
or you might prefer:
var date = new Date(), y = date.getFullYear(), m = date.getMonth();
var firstDay = new Date(y, m, 1);
var lastDay = new Date(y, m...
How to get a list of all valid IP addresses in a local network? [closed]
...
410
Install nmap,
sudo apt-get install nmap
then
nmap -sP 192.168.1.*
or more commonly
nmap ...
C++ convert from 1 char to string? [closed]
I need to cast only 1 char to string . The opposite way is pretty simple like str[0] .
2 Answers
...
check / uncheck checkbox using jquery? [duplicate]
...
1277
For jQuery 1.6+ :
.attr() is deprecated for properties; use the new .prop() function instea...
c++提取复数的实部和虚部 - C/C++ - 清泛网 - 专注C/C++及内核技术
...p, 0, sizeof(COMPLEX));
char buf[MAX_BUF_LEN];
int signPos = -1, // +/-号位置
iPos = -1; // 结尾的i的位置
for (int i = len-1; i >-1; i--)
{
if ('i' == strCplx[i])
iPos = i;
else if ('+' == strCplx[i] || '-' == strCplx[...