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Is there a difference between foo(void) and foo() in C++ or C?
...ied type"
void foo(void) means "a function foo taking no arguments"
In C++:
void foo() means "a function foo taking no arguments"
void foo(void) means "a function foo taking no arguments"
By writing foo(void), therefore, we achieve the same interpretation across both languages and make o...
Read file line by line using ifstream in C++
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Reading a file line by line in C++ can be done in some different ways.
[Fast] Loop with std::getline()
The simplest approach is to open an std::ifstream and loop using std::getline() calls. The code is clean and easy to understand.
#include <fstream&...
What are all the common undefined behaviours that a C++ programmer should know about? [closed]
What are all the common undefined behaviours that a C++ programmer should know about?
11 Answers
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What do the following phrases mean in C++: zero-, default- and value-initialization?
What do the following phrases mean in C++:
2 Answers
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How to enable C++11/C++0x support in Eclipse CDT?
... Eclipse Indigo 20110615-0604 on Windows with a Cygwin setup.
Make a new C++ project
Default options for everything
Once created, right-click the project and go to "Properties"
C/C++ Build -> Settings -> Tool Settings -> GCC C++ Compiler -> Miscellaneous -> Other Flags. Put -std=c+...
Why should I use a pointer rather than the object itself?
I'm coming from a Java background and have started working with objects in C++. But one thing that occurred to me is that people often use pointers to objects rather than the objects themselves, for example this declaration:
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Regular cast vs. static_cast vs. dynamic_cast [duplicate]
I've been writing C and C++ code for almost twenty years, but there's one aspect of these languages that I've never really understood. I've obviously used regular casts i.e.
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'typeid' versus 'typeof' in C++
I am wondering what the difference is between typeid and typeof in C++. Here's what I know:
6 Answers
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C++ templates that accept only certain types
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C++11 has come. Now we can use static_assert(std::is_base_of<List, T>::value, "T must extend list").
– Siyuan Ren
Sep 10 '13 at 2:55
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Why is there no Constant feature in Java?
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Every time I go from heavy C++ coding to Java, it takes me a little while to adapt to the lack of const-correctness in Java. This usage of const in C++ is much different than just declaring constant variables, if you didn't know. Essentially, it ensu...