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Validating parameters to a Bash script
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10 Answers
10
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Extract a regular expression match
...nd adds a few that are missing:
library(stringr)
str_locate("aaa12xxx", "[0-9]+")
# start end
# [1,] 4 5
str_extract("aaa12xxx", "[0-9]+")
# [1] "12"
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BigDecimal - to use new or valueOf
...an be somewhat unpredictable. One might assume that writing new BigDecimal(0.1) in Java creates a BigDecimal which is exactly equal to 0.1 (an unscaled value of 1, with a scale of 1), but it is actually equal to 0.1000000000000000055511151231257827021181583404541015625. This is because 0.1 cannot be...
Determine the path of the executing BASH script [duplicate]
...etermine the directory path of the currently executing script using %~dp0 . For example:
5 Answers
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Replace all elements of Python NumPy Array that are greater than some value
...o replace all values in it greater than or equal to a threshold T with 255.0. To my knowledge, the most fundamental way would be:
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How to detect IE11?
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{
var ua = navigator.userAgent;
var re = new RegExp("MSIE ([0-9]{1,}[\\.0-9]{0,})");
if (re.exec(ua) != null)
rv = parseFloat( RegExp.$1 );
}
else if (navigator.appName == 'Netscape')
{
var ua = navigator.userAgent;
var re = new RegExp("Trident/.*rv:([0...
stash@{1} is ambiguous?
I'm trying to get info about my stash, but git is telling me that stash@{0} and stash@{1} are ambiguous. git stash list works fine, and .git/logs/refs/stash seems to have the appropriate content (not that I'm an expert on git internals).
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Question mark and colon in JavaScript
...f the ? as "then" and : as "else".
Your code is equivalent to
if (max != 0)
hsb.s = 255 * delta / max;
else
hsb.s = 0;
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Calculate last day of month in JavaScript
If you provide 0 as the dayValue in Date.setFullYear you get the last day of the previous month:
20 Answers
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Transitions on the CSS display property
...rder: 1px solid #eee;
}
div > ul {
visibility: hidden;
opacity: 0;
transition: visibility 0s, opacity 0.5s linear;
}
div:hover > ul {
visibility: visible;
opacity: 1;
}
<div>
<ul>
<li>Item 1</li>
<li>Item 2</li>
<li&...