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How to generate a create table script for an existing table in phpmyadmin?

How can I generate a create table script for an existing table in phpmyadmin? 10 Answers ...
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No module named pkg_resources

... Reported the bug to CentOS.org bugs.centos.org/view.php?id=14042 – rjt Oct 20 '17 at 19:22 ...
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Is there any WinSCP equivalent for linux? [closed]

...t) Download latest WinSCP portable package https://winscp.net/eng/download.php Make a folder and put the content of zip file in this folder Open a terminal Type wine WinSCP.exe Done! WinSCP will run like in Windows environment! Best regards. ...
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jQuery scroll to element

... edited Jul 8 '18 at 14:48 php_nub_qq 11.9k1717 gold badges5454 silver badges117117 bronze badges answered Jul 13 '11 at 9:52 ...
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Static Block in Java [duplicate]

...led explanation. http://www.jusfortechies.com/java/core-java/static-blocks.php share | improve this answer | follow | ...
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Meaning of $? (dollar question mark) in shell scripts

...about to do vendor/bin/drush status bootstrap | grep -q $(vendor/bin/drush php-eval 'if (function_exists("t")) echo t("Successful");') &> /dev/null;. If I had to put that in a single line if [ ... ] it would be terribly unreadable. I plan to store the output of that line to a variable so I ca...
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Shell Script — Get all files modified after

I'd rather not do this in PHP so I'm hoping a someone decent at shell scripting can help. 9 Answers ...
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Good Haskell source to read and learn from [closed]

... This is typical haskell damit. With php you read a hello world and go straight on writing poor web-sites. With haskell, there is no upper bound on what you can learn, there's always more interesting extensions and papers coming up. And just now I learned that u...
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How to screenshot website in JavaScript client-side / how Google did it? (no need to access HDD) [du

...o get the outer HTML and pass it to GrabzIt's API. – PHP Rocks May 11 '18 at 10:34 add a comment  |  ...
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Ajax tutorial for post and get [closed]

...Id = $("ul.nav").first().attr("id"); var request = $.ajax({ url: "script.php", type: "POST", data: {id : menuId}, dataType: "html" }); request.done(function(msg) { $("#log").html( msg ); }); request.fail(function(jqXHR, textStatus) { alert( "Request failed: " + textStatus ); }); ...