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Ruby, !! operator (a/k/a the double-bang) [duplicate]
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So basically, !!foo is equivalent to not (foo == nil or foo == false)
– FloatingRock
Mar 30 '17 at 15:43
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What is a covariant return type?
...ct. You could override this in your own class as follows:
public class MyFoo
{
...
// Note covariant return here, method does not just return Object
public MyFoo clone()
{
// Implementation
}
}
The benefit here is that any method which holds an explicit reference to a MyF...
Where is the syntax for TypeScript comments documented?
...dmap
Current
TypeScript uses JSDoc. e.g.
/** This is a description of the foo function. */
function foo() {
}
To learn jsdoc : https://jsdoc.app/
But you don't need to use the type annotation extensions in JSDoc.
You can (and should) still use other jsdoc block tags like @returns etc.
Example
Jus...
Why does X[Y] join of data.tables not allow a full outer join, or a left join?
...Y) does both ways at the same time. The number of rows of X[Y] and Y[X] usually differ, whereas the number of rows returned by merge(X,Y) and merge(Y,X) is the same.
BUT that misses the main point. Most tasks require something to be done on the
data after a join or merge. Why merge all the co...
initializer_list and move semantics
Am I allowed to move elements out of a std::initializer_list<T> ?
8 Answers
8
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Difference between app.use and app.get in express.js
...nt" path, app.use() will respond to any path that starts with /, which are all of them and regardless of HTTP verb used:
GET /
PUT /foo
POST /foo/bar
etc.
app.get(), on the other hand, is part of Express' application routing and is intended for matching and handling a specific route when request...
Can I use GDB to debug a running process?
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Yes you can. Assume a process foo is running...
ps -elf | grep foo
look for the PID number
gdb -a {PID number}
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How to split a string into a list?
...d, it might be a typo, but you have your loop a little messed up. If you really did want to use append, it would be:
words.append(word)
not
word.append(words)
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Get escaped URL parameter
... you may want "decodeURIComponent()" instead of "decodeURI()", especially if you are passing interesting data like return URLs in as a URL parameter
– perfectionist
Feb 27 '12 at 13:14
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How to set DOM element as the first child?
I have element E and I'm appending some elements to it. All of a sudden, I find out that the next element should be the first child of E. What's the trick, how to do it? Method unshift doesn't work because E is an object, not array.
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