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jQuery equivalent of getting the context of a Canvas
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Try:
$("#canvas")[0].getContext('2d');
jQuery exposes the actual DOM element in numeric indexes, where you can perform normal JavaScript/DOM functions.
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Printf width specifier to maintain precision of floating-point value
...n:
#include <float.h>
int Digs = DECIMAL_DIG;
double OneSeventh = 1.0/7.0;
printf("%.*e\n", Digs, OneSeventh);
// 1.428571428571428492127e-01
But let's dig deeper ...
Mathematically, the answer is "0.142857 142857 142857 ...", but we are using finite precision floating point numbers.
Let...
how to override left:0 using CSS or Jquery?
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answered Apr 11 '12 at 9:06
Jan HančičJan Hančič
48.2k1515 gold badges8787 silver badges9494 bronze badges
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How do I check the difference, in seconds, between two dates?
...tes, use total_seconds like this:
import datetime as dt
a = dt.datetime(2013,12,30,23,59,59)
b = dt.datetime(2013,12,31,23,59,59)
(b-a).total_seconds()
86400.0
#note that seconds doesn't give you what you want:
(b-a).seconds
0
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Calculate last day of month in JavaScript
If you provide 0 as the dayValue in Date.setFullYear you get the last day of the previous month:
20 Answers
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How to get an enum which is created in attrs.xml in code
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101
There does not seem to be an automated way to get a Java enum from an attribute enum - in Java ...
How to remove last n characters from every element in the R vector
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answered May 1 '14 at 17:50
nfmcclurenfmcclure
2,25711 gold badge1919 silver badges3535 bronze badges
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Date.getDay() javascript returns wrong day
...lue returned by getDay is an integer corresponding to the day of the week: 0 for Sunday, 1 for Monday, 2 for Tuesday, and so on.
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Format date to MM/dd/yyyy in JavaScript [duplicate]
I have a dateformat like this '2010-10-11T00:00:00+05:30' . I have to format in to MM/dd/yyyy using JavaScript or jQuery . Anyone help me to do the same.
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Print all day-dates between two dates [duplicate]
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I came up with this:
from datetime import date, timedelta
sdate = date(2008, 8, 15) # start date
edate = date(2008, 9, 15) # end date
delta = edate - sdate # as timedelta
for i in range(delta.days + 1):
day = sdate + timedelta(days=i)
print(day)
The output:
2008-08-15
2008-...