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Tricky Google interview question
...; v(n);
v[0] = 1;
int i2 = 0; // Index for 2
int i5 = 0; // Index for 5
int x2 = 2 * v[i2]; // Next two candidates
int x5 = 5 * v[i5];
for (int i = 1; i != n; ++i)
{
int m = std::min(x2, x5);
std::cout << m << " "...
MySQL Select minimum/maximum among two (or more) given values
...
WHERE B.x = A.x
Both are described here http://dev.mysql.com/doc/refman/5.0/en/comparison-operators.html
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