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Defining a variable with or without export
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export makes the variable available to sub-processes.
That is,
export name=value
means that the variable name is available to any process you run from that shell process. If you want a process to make use of this variable, use export, and run ...
Python multiprocessing pool.map for multiple arguments
In the Python multiprocessing library, is there a variant of pool.map which supports multiple arguments?
19 Answers
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R - Concatenate two dataframes?
Given two dataframes a and b :
5 Answers
5
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Test whether a Ruby class is a subclass of another class
I would like to test whether a class inherits from another class, but there doesn't seem to exist a method for that.
2 Answ...
List all base classes in a hierarchy of given class?
... (whether it is a new-style class or not), how do you generate all the base classes - anywhere in the inheritance hierarchy - it issubclass of?
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how to compare two elements in jquery [duplicate]
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You could compare DOM elements. Remember that jQuery selectors return arrays which will never be equal in the sense of reference equality.
Assuming:
<div id="a" class="a"></div>
this:
$('div.a')[0] == $('div#a')[0]
returns true.
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Why does Google +1 record my mouse movements? [closed]
This is only on pages with a Google +1 box on my website:
9 Answers
9
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How do I convert a pandas Series or index to a Numpy array? [duplicate]
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To get a NumPy array, you should use the values attribute:
In [1]: df = pd.DataFrame({'A': [1, 2, 3], 'B': [4, 5, 6]}, index=['a', 'b', 'c']); df
A B
a 1 4
b 2 5
c 3 6
In [2]: df.index.values
Out[2]: array(['a', 'b', 'c'], dtype=object)
This accesses how the data ...
Method Resolution Order (MRO) in new-style classes?
In the book Python in a Nutshell (2nd Edition) there is an example which uses
old style classes to demonstrate how methods are resolved in classic resolution order and
how is it different with the new order.
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How to find common elements from multiple vectors?
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There might be a cleverer way to go about this, but
intersect(intersect(a,b),c)
will do the job.
EDIT: More cleverly, and more conveniently if you have a lot of arguments:
Reduce(intersect, list(a,b,c))
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