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UINavigationController “back button” custom text?
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This is the best answer I found so far.
– Ayan Sengupta
Mar 8 '14 at 21:15
2
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Do you use source control for your database items? [closed]
...ine-grained control over schema and data changes, and works very well as a best practice for database source control. The part which can be tricky and adds almost as much security as the rest of the process is a tool to help manage the scripts. It can be as simple as file concatenation, or as compl...
Best way to add “current” class to nav in Rails 3
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Your way suit best when there are some pages handled by different controller / actions but in the same menu item, right? Have you encountered more advantages~?
– PeterWong
Sep 15 '10 at 2:39
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Storing integer values as constants in Enum manner in java [duplicate]
...teger constants which also require you not to renumber them. However it is best to use a system like:
public enum PAGE{
SIGN_CREATE0(0), SIGN_CREATE(1) ,HOME_SCREEN(2), REGISTER_SCREEN(3)
private int id;
PAGE(int id){
this.id = id;
}
public int getID(){
return id;
}
}
You ...
getting the last item in a javascript object
... at other times be banana and so on. If you need to rely on ordering, your best bet is to go with arrays. The power of key-value data structures lies in accessing values by their keys, not in being able to get the nth item of the object.
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How can I find a specific element in a List?
...reak; // If you only want to find the first instance a break here would be best for your application
}
}
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Remove all values within one list from another list? [duplicate]
.... Using 'remove' is ~50 times faster, but it modifies source list.
And the best choice is using sets - it's more than 1000 times faster than list comprehension!
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How to handle both a single item and an array for the same property using JSON.net
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The best way to handle this situation is to use a custom JsonConverter.
Before we get to the converter, we'll need to define a class to deserialize the data into. For the Categories property that can vary between a single item ...
jQuery: Count number of list elements?
... preferred because it doesn't have the overhead of a function call.
So the best way:
$("#mylist li").length
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How to determine if Javascript array contains an object with an attribute that equals a given value?
...g for */
}
EDIT: If you need compatibility with lousy browsers then your best bet is:
if (vendors.filter(function(e) { return e.Name === 'Magenic'; }).length > 0) {
/* vendors contains the element we're looking for */
}
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