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Does the ternary operator exist in R?
...(x)]])
here, you don't need to take care about brackets:
> 1 ? 2*3 : 4
[1] 6
> 0 ? 2*3 : 4
[1] 4
> TRUE ? x*2 : 0
[1] 2
> FALSE ? x*2 : 0
[1] 0
but you need brackets for assignment :(
> y <- 1 ? 2*3 : 4
[1] 6
> y
[1] 1
> y <- (1 ? 2*3 : 4)
> y
[1] 6
Finally, y...
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edited May 10 '16 at 11:44
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simhumileco
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answered Nov 20 '11 at 21:43
Joe KingtonJoe Kington
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