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How to find and return a duplicate value in array
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a = ["A", "B", "C", "B", "A"]
a.detect{ |e| a.count(e) > 1 }
I know this isn't very elegant answer, but I love it. It's beautiful one liner code. And works perfectly fine unless you need to process huge data set.
Looking for faster solution? Here you go!
def find_one_using_hash_map(ar...
Viewing all defined variables [duplicate]
I'm currently working on a computation in python shell. What I want to have is Matlab style listout where you can see all the variables that have been defined up to a point (so I know which names I've used, their values and such).
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Which sort algorithm works best on mostly sorted data? [closed]
Which sorting algorithm works best on mostly sorted data?
20 Answers
20
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Disabling and enabling a html input button
So I have a button like this:
11 Answers
11
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CreateElement with id?
...an ID, however I have not found anything on google, and idName does not work. I read something about append , however it seems pretty complicated for a task that seems pretty simple, so is there an alternative? Thanks :)
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Creating dataframe from a dictionary where entries have different lengths
Say I have a dictionary with 10 key-value pairs. Each entry holds a numpy array. However, the length of the array is not the same for all of them.
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How can I convert an image into a Base64 string?
What is the code to transform an image (maximum of 200 KB) into a Base64 String?
14 Answers
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Algorithm to find Largest prime factor of a number
...nt ways to find factors of big numbers (for smaller ones trial division works reasonably well).
One method which is very fast if the input number has two factors very close to its square root is known as Fermat factorisation. It makes use of the identity N = (a + b)(a - b) = a^2 - b^2 and is easy ...
JavaScript is in array
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Try this:
if(blockedTile.indexOf("118") != -1)
{
// element found
}
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Passing a method as a parameter in Ruby
.... Therefor I try to implement the algorithms (given in Python) from the book "Programming Collective Intelligence" Ruby.
8 ...