大约有 740 项符合查询结果（耗时：0.0091秒） [XML]
What is considered a good response time for a dynamic, personalized web application? [closed]
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Maybe 2000 milliseconds and 10000 ms?
– Bob
Jun 14 '14 at 16:19
9
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Why are flag enums usually defined with hexadecimal values
...10
Flag3 = 0x4, // == 00100
Flag4 = 0x8, // == 01000
Flag5 = 0x10 // == 10000
Though the progression makes it even clearer:
Flag6 = 0x20 // == 00100000
Flag7 = 0x40 // == 01000000
Flag8 = 0x80 // == 10000000
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How to calculate the number of occurrence of a given character in each row of a column of strings?
...ot"), stringsAsFactors = FALSE)
test.data <- q.data[rep(1:NROW(q.data), 10000),]
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Best way to detect when a user leaves a web page?
...enough amount that there won't be false positives
const liveTimeoutDelay = 10000
let liveTimeout = null
global.self.addEventListener('fetch', event => {
clearTimeout(liveTimeout)
liveTimeout = setTimeout(() => {
console.log('User left page')
// handle page leave
}, liveTimeoutDe...
What MySQL data type should be used for Latitude/Longitude with 8 decimal places?
...DECIMAL (10, 8) or FLOAT (10, 8)) I calculate 0.3 / 3 then DECIMAL gives 0.100000000000 (correct), and float gives 0.100000003974 (correct to 8dp, but would be wrong if multiplied). I understand the main difference is in how the numbers are stored. DECIMAL stores the decimal digits, where FLOAT stor...
How to declare a variable in MySQL?
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-- Syntax to Set value to a Global variable:
SET GLOBAL sort_buffer_size=1000000;
SET @@global.sort_buffer_size=1000000;
-- Syntax to Set value to a Session variable:
SET sort_buffer_size=1000000;
SET SESSION sort_buffer_size=1000000;
SET @@sort_buffer_size=1000000;
SET @@local.sort_buffer_size=1...
Is it possible to break a long line to multiple lines in Python [duplicate]
...pathname = (
'/home/acgtyrant/BigDatas/'
'model_configs/lenet_iter_10000.caffemodel')
Do not add any comma, or you will get a tuple which contains many strs!
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How to measure time taken between lines of code in python?
... code here with time.sleep(10) and got 0.0 seconds. Adding for i in range(10000):/pass produced the same results. Under any circumstances I tried, time.process_time() always returns the same number. I got expected results using time.perf_counter() though
– biscuit314
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Find the most frequent number in a numpy vector
...()[0][0]
3
>>> %timeit collections.Counter(a).most_common()[0][0]
100000 loops, best of 3: 11.3 µs per loop
>>>
>>> import numpy
>>> numpy.bincount(a).argmax()
3
>>> %timeit numpy.bincount(a).argmax()
100 loops, best of 3: 2.84 ms per loop
>>> ...
Fastest way to find second (third…) highest/lowest value in vector or column
...chmarks below against most popular answers.
For 10 thousand numbers:
N = 10000
x = rnorm(N)
maxN <- function(x, N=2){
len <- length(x)
if(N>len){
warning('N greater than length(x). Setting N=length(x)')
N <- length(x)
}
sort(x,partial=len-N+1)[len-N+1]...