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Determine a string's encoding in C#

... answered Feb 6 '10 at 17:31 devdimidevdimi 2,3561818 silver badges1717 bronze badges ...
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Redis - Connect to Remote Server

...the Quick Start guide on http://redis.io/topics/quickstart on my Ubuntu 10.10 server. I'm running the service as dameon (so it can be run by init.d) ...
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Can I set an opacity only to the background image of a div?

...ndex: 1; } .myDiv .bg { position: absolute; z-index: -1; top: 0; bottom: 0; left: 0; right: 0; background: url(test.jpg) center center; opacity: .4; width: 100%; height: 100%; } See test case on jsFiddle :before and ::before pseudo-element Another trick i...
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Calling shell functions with xargs

...orting the function should do it (untested): export -f echo_var seq -f "n%04g" 1 100 | xargs -n 1 -P 10 -I {} bash -c 'echo_var "$@"' _ {} You can use the builtin printf instead of the external seq: printf "n%04g\n" {1..100} | xargs -n 1 -P 10 -I {} bash -c 'echo_var "$@"' _ {} Also, using ret...
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Formatting “yesterday's” date in python

... 406 Use datetime.timedelta() >>> from datetime import date, timedelta >>> yester...
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Underscore: sortBy() based on multiple attributes

...dArray = _(patients).chain().sortBy(function(patient) { return patient[0].name; }).sortBy(function(patient) { return patient[0].roomNumber; }).value(); When the second sortBy finds that John and Lisa have the same room number it will keep them in the order it found them, which the first so...
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Get number days in a specified month using JavaScript? [duplicate]

... 609 // Month here is 1-indexed (January is 1, February is 2, etc). This is // because we're using 0...
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What is the result of % in Python?

... 310 The % (modulo) operator yields the remainder from the division of the first argument by the s...
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Java 8: performance of Streams vs Collections

...Vanilla.N) public class StreamVsVanilla { public static final int N = 10000; static List<Integer> sourceList = new ArrayList<>(); static { for (int i = 0; i < N; i++) { sourceList.add(i); } } @Benchmark public List<Double> va...
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Check if a value is within a range of numbers

...e. You don't need "multiple if" statements to do it, either: if (x >= 0.001 && x <= 0.009) { // something } You could write yourself a "between()" function: function between(x, min, max) { return x >= min && x <= max; } // ... if (between(x, 0.001, 0.009)) { //...