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Render a string in HTML and preserve spaces and linebreaks
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I guess the 'problem' with MVC is that if I change the string as you suggest it will display the ' ' instead of the spaces, unless I use @Html.Raw(). Then I have to be concerned about xss and the user entering bad html. I could however encode the strings on insert so tha...
How to install Hibernate Tools in Eclipse?
...rrently working), but I will consult your link once I determine I need the extra automation provided by Hibernate Tools.
– Withheld
Oct 22 '13 at 13:35
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JavaScript naming conventions [closed]
...ink, I can't believe a "link answer" has so many votes. You could at least extract & format the relevant parts of the linked page.
– Adrien Be
Nov 13 '14 at 9:26
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AngularJS : The correct way of binding to a service properties
...Timer.data in a $watch, Timer has to be defined on the $scope, because the string expression you pass to $watch is evaluated against the scope. Here is a plunker that shows how to make that work. The objectEquality parameter is documented here -- 3rd parameter -- but not really explained too well....
How to get Time from DateTime format in SQL?
...AttDate as time) [time]
FROM yourtable
Earlier versions:
SELECT convert(char(5), AttDate, 108) [time]
FROM yourtable
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半个汉字的校验与处理(C++) - C/C++ - 清泛网 - 专注C/C++及内核技术
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// strSrc: 原始字符串
// nMaxLen: 截断后的最大长度
char *GetTruncate(char *strSrc, int nMaxLen)
{
if (strSrc == NULL || nMaxLen == 0)
{
return NULL;
}
int len = strlen(strSrc);
if (len == 0)
{
...
C语言面试那些事儿──一道指针与数组问题 - C/C++ - 清泛网 - 专注C/C++及内核技术
...─一道指针与数组问题首先看如下代码：int main(int argc, char** argv){ int a[5] = {1,2,3,4,5}; int* ptr = (int*)(&a + 1); ...首先看如下代码：
int main(int argc, char** argv)
{
int a[5] = {1,2,3,4,5};
int* ptr = (int*)(&a + 1);
printf("%d,%d\n", *(a+1...
error C2758: “ConstInit::cival”: 必须在构造函数基/成员初始值设定项列...
... int ival;
const int cival;
int &rival;
};
int main(int argc, char *argv[])
{
ConstInit ci;
}
这里引用类型rival以及const类型cival都没有在初始化列表中初始化，因此报错。解决办法就是在初始化列表中初始化这些特殊的类成员。如下...
How to post JSON to PHP with curl
...ng an empty array because PHP is expecting the posted data to be in a Querystring format (key=value&key1=value1).
Try changing your curl request to:
curl -i -X POST -d 'json={"screencast":{"subject":"tools"}}' \
http://localhost:3570/index.php/trainingServer/screencast.json
and see if...
Is it good practice to use java.lang.String.intern()?
The Javadoc about String.intern() doesn't give much detail. (In a nutshell: It returns a canonical representation of the string, allowing interned strings to be compared using == )
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