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Is storing a delimited list in a database column really that bad?

...es (any or all of them can be selected). I chose to save them in a comma separated list of values stored in one column of the database table. ...
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How do I print the full value of a long string in gdb?

I want to print the full length of a C-string in GDB. By default it's being abbreviated, how do I force GDB to print the whole string? ...
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Understanding Linux /proc/id/maps

I am trying to understand my embedded Linux application's memory use. The /proc/pid/maps utility/file seems to be a good resource for seeing the details. Unfortunately I don't understand all the columns and entries. ...
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Can I get the name of the current controller in the view?

... share | improve this answer | follow | edited Feb 3 '17 at 11:04 mb21 25.4k55 gol...
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Different class for the last element in ng-repeat

I am creating a list using ng-repeat something like this 6 Answers 6 ...
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What does [].forEach.call() do in JavaScript?

I was looking at some snippets of code, and I found multiple elements calling a function over a node list with a forEach applied to an empty array. ...
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Difference between .keystore file and .jks file

... I know jks is for "Java keystore" and both are a way to store key/value pairs. 3 Answers ...
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How to split a sequence into two pieces by predicate?

How do I split a sequence into two lists by a predicate? 6 Answers 6 ...
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map function for objects (instead of arrays)

... There is no native map to the Object object, but how about this: var myObject = { 'a': 1, 'b': 2, 'c': 3 }; Object.keys(myObject).map(function(key, index) { myObject[key] *= 2; }); console.log(myObject); // => { 'a': 2, 'b': 4,...
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Using NSPredicate to filter an NSArray based on NSDictionary keys

...e data variable is actually an array containing a dictionary with the key SPORT NSArray *data = [NSArray arrayWithObject:[NSMutableDictionary dictionaryWithObject:@"foo" forKey:@"BAR"]]; NSArray *filtered = [data filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(BAR == %@)", @"foo...