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How do you represent a JSON array of strings?
This is all you need for valid JSON, right?
4 Answers
4
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How to parse a JSON string into JsonNode in Jackson?
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What did passing in JsonNode.class actually get you here?
– David
Oct 24 '13 at 18:10
3
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Remove last item from array
...n.js"></script>
<b>Original Array : </b>
<div id="div1"></div>
<br/>
<b>After slice(0, -1): </b>
<div id="div2"></div>
instead of doing :
arr.slice(-1); // returns [2]
Here is a demo:
var arr = [1, 0, 2];
var ne...
What is the fastest method for selecting descendant elements in jQuery?
...
Method 1 and method 2 are identical with the only difference is that method 1 needs to parse the scope passed and translate it to a call to $parent.find(".child").show();.
Method 4 and Method 5 both need to parse the selector and then just call: $('...
how to customize `show processlist` in mysql?
...ng like:
mysql show processlist
| grep -v '^\+\-\-'
| grep -v '^| Id'
| sort -n -k12
The two greps strip out the header and trailer lines (others may be needed if there are other lines not containing useful information) and the sort is done based on the numeric field number 12 (I thin...
Regex using javascript to return just numbers
...'.match( numberPattern )
This would return an Array with two elements inside, '102' and '1948948'. Operate as you wish. If it doesn't match any it will return null.
To concatenate them:
'something102asdfkj1948948'.match( numberPattern ).join('')
Assuming you're not dealing with complex decimal...
Paging with Oracle
... a.*, rownum r__
FROM
(
SELECT * FROM ORDERS WHERE CustomerID LIKE 'A%'
ORDER BY OrderDate DESC, ShippingDate DESC
) a
WHERE rownum < ((pageNumber * pageSize) + 1 )
)
WHERE r__ >= (((pageNumber-1) * pageSize) + 1)
...
How to make a div fill a remaining horizontal space?
I have 2 divs: one in the left side and one in the right side of my page. The one in the left side has fixed width and I want the one of the right side to fill the remaining space.
...
Update multiple rows in same query using PostgreSQL
... as c(column_b, column_a, column_c)
where c.column_b = t.column_b;
sql fiddle demo
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Fetch the row which has the Max value for a column
...my_date column value is equal to the maximum value of my_date for that userid. This may retrieve multiple rows for the userid where the maximum date is on multiple rows.
select userid,
my_date,
...
from
(
select userid,
my_date,
...
max(my_date) over (partition by...
