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Get local IP address in node.js
... net of nets[name]) {
// skip over non-ipv4 and internal (i.e. 127.0.0.1) addresses
if (net.family === 'IPv4' && !net.internal) {
if (!results[name]) {
results[name] = [];
}
results[name].push(net.address);
}
}
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vertical & horizontal lines in matplotlib
...is range, regardless of coordinates. The parameters xmin or ymin use value 0.0 as the minimum of the axis and 1.0 as the maximum of the axis.
Instead, use plt.plot((x1, x2), (y1, y2), 'k-') to draw a line from the point (x1, y1) to the point (x2, y2) in color k. See pyplot.plot.
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Select random row from a sqlite table
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answered Feb 17 '10 at 10:06
Adriaan StanderAdriaan Stander
146k2626 gold badges261261 silver badges272272 bronze badges
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How can I get a count of the total number of digits in a number?
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Without converting to a string you could try:
Math.Ceiling(Math.Log10(n));
Correction following ysap's comment:
Math.Floor(Math.Log10(n) + 1);
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Is it safe to use -1 to set all bits to true?
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20 Answers
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Convert HH:MM:SS string to seconds only in javascript
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Try this:
var hms = '02:04:33'; // your input string
var a = hms.split(':'); // split it at the colons
// minutes are worth 60 seconds. Hours are worth 60 minutes.
var seconds = (+a[0]) * 60 * 60 + (+a[1]) * 60 + (+a[2]);
console.log(seconds...
Regular expression for a hexadecimal number?
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How about the following?
0[xX][0-9a-fA-F]+
Matches expression starting with a 0, following by either a lower or uppercase x, followed by one or more characters in the ranges 0-9, or a-f, or A-F
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Stream.Seek(0, SeekOrigin.Begin) or Position = 0
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answered Aug 30 '11 at 5:22
gordygordy
7,92911 gold badge2626 silver badges3939 bronze badges
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Subscripts in plots in R
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answered Apr 14 '12 at 19:05
smusmu
7,04722 gold badges1616 silver badges1414 bronze badges
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Javascript swap array elements
... = list[y];
list[y] = list[x];
list[x] = b;
Edit hijacking top answer 10 years later with a lot of ES6 adoption under our belts:
Given the array arr = [1,2,3,4], you can swap values in one line now like so:
[arr[0], arr[1]] = [arr[1], arr[0]];
This would produce the array [2,1,3,4]. This is ...
