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C# Entity-Framework: How can I combine a .Find and .Include on a Model Object?
...gory)
.Include(i => i.Brand)
.FistOrDefault(m>x m> => m>x m>.ItemId == id);
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What does |= (single pipe equal) and &=(single ampersand equal) mean
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They're compound assignment operators, translating (very loosely)
m>x m> |= y;
into
m>x m> = m>x m> | y;
and the same for &. There's a bit more detail in a few cases regarding an implicit cast, and the target variable is only evaluated once, but that's basically the gist of it.
In terms of the n...
Count number of occurrences of a pattern in a file (even on same line)
...c -l
2
Two matches are found in the line (a{foo}bar{foo}bar) because we em>x m>plicitly asked to find every occurrence (-o). Every occurence is printed on a separate line, and wc -l just counts the number of lines in the output.
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Take the content of a list and append it to another list
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You probably want
list2.em>x m>tend(list1)
instead of
list2.append(list1)
Here's the difference:
>>> a = range(5)
>>> b = range(3)
>>> c = range(2)
>>> b.append(a)
>>> b
[0, 1, 2, [0, 1, 2, 3, 4]]
>&gt...
Compare if two variables reference the same object in python
...
That’s what is is for: m>x m> is y returns True if m>x m> and y are the same object.
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how to make svn diff show only non-whitespace line changes between two revisions
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You can use
svn diff -r 100:200 -m>x m> -b > file.diff
If you want to ignore all whitespaces:
svn diff -m>x m> -w | less
Source
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What does the star operator mean, in a function call?
What does the * operator mean in Python, such as in code like zip(*m>x m>) or f(**k) ?
5 Answers
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In Python, if I return inside a “with” block, will the file still close?
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Yes, it acts like the finally block after a try block, i.e. it always em>x m>ecutes (unless the python process terminates in an unusual way of course).
It is also mentioned in one of the em>x m>amples of PEP-343 which is the specification for the with statement:
with locked(myLock):
# Code here em>x m>ec...
The most efficient way to implement an integer based power function pow(int, int)
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Em>x m>ponentiation by squaring.
int ipow(int base, int em>x m>p)
{
int result = 1;
for (;;)
{
if (em>x m>p & 1)
result *= base;
em>x m>p >>= 1;
if (!em>x m>p)
break;
base ...
How does generic lambda work in C++14?
...ere introduced in C++14.
Simply, the closure type defined by the lambda em>x m>pression will have a templated call operator rather than the regular, non-template call operator of C++11's lambdas (of course, when auto appears at least once in the parameter list).
So your em>x m>ample:
auto glambda = [] (a...