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C# Entity-Framework: How can I combine a .Find and .Include on a Model Object?
...gory)
.Include(i => i.Brand)
.FistOrDefault(m>x m> => m>x m>.ItemId == id);
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What does |= (single pipe equal) and &=(single ampersand equal) mean
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They're compound assignment operators, translating (very loosely)
m>x m> |= y;
into
m>x m> = m>x m> | y;
and the same for &. There's a bit more detail in a few cases regarding an implicit cast, and the target variable is only evaluated once, but that's basically the gist of it.
In terms of the n...
Take the content of a list and append it to another list
...
You probably want
list2.em>x m>tend(list1)
instead of
list2.append(list1)
Here's the difference:
>>> a = range(5)
>>> b = range(3)
>>> c = range(2)
>>> b.append(a)
>>> b
[0, 1, 2, [0, 1, 2, 3, 4]]
>&gt...
Count number of occurrences of a pattern in a file (even on same line)
...c -l
2
Two matches are found in the line (a{foo}bar{foo}bar) because we em>x m>plicitly asked to find every occurrence (-o). Every occurence is printed on a separate line, and wc -l just counts the number of lines in the output.
...
Compare if two variables reference the same object in python
...
That’s what is is for: m>x m> is y returns True if m>x m> and y are the same object.
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how to make svn diff show only non-whitespace line changes between two revisions
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You can use
svn diff -r 100:200 -m>x m> -b > file.diff
If you want to ignore all whitespaces:
svn diff -m>x m> -w | less
Source
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What does the star operator mean, in a function call?
What does the * operator mean in Python, such as in code like zip(*m>x m>) or f(**k) ?
5 Answers
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In Python, if I return inside a “with” block, will the file still close?
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Yes, it acts like the finally block after a try block, i.e. it always em>x m>ecutes (unless the python process terminates in an unusual way of course).
It is also mentioned in one of the em>x m>amples of PEP-343 which is the specification for the with statement:
with locked(myLock):
# Code here em>x m>ec...
The most efficient way to implement an integer based power function pow(int, int)
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Em>x m>ponentiation by squaring.
int ipow(int base, int em>x m>p)
{
int result = 1;
for (;;)
{
if (em>x m>p & 1)
result *= base;
em>x m>p >>= 1;
if (!em>x m>p)
break;
base ...
How does generic lambda work in C++14?
...ere introduced in C++14.
Simply, the closure type defined by the lambda em>x m>pression will have a templated call operator rather than the regular, non-template call operator of C++11's lambdas (of course, when auto appears at least once in the parameter list).
So your em>x m>ample:
auto glambda = [] (a...