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Difference between Math.Floor() and Math.Truncate()

... | edited May 23 '17 at 12:03 Community♦ 111 silver badge answered Aug 1 '08 at 12:26 ...
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Transposing a 2D-array in JavaScript

... 23 Answers 23 Active ...
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Integrate ZXing in Android Studio

... 234 I was integrating ZXING into an Android application and there were no good sources for the inpu...
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Best way to iterate through a Perl array

...he array elements occurs. ($_ is aliased to the element in #1, but #2 and #3 actually copy the scalars from the array.) #5 might be similar. In terms memory usage: They're all the same except for #5. for (@a) is special-cased to avoid flattening the array. The loop iterates over the indexes of the...
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Finding sum of elements in Swift array

... This is the easiest/shortest method I can find. Swift 3 and Swift 4: let multiples = [...] let sum = multiples.reduce(0, +) print("Sum of Array is : ", sum) Swift 2: let multiples = [...] sum = multiples.reduce(0, combine: +) Some more info: This uses Array's reduce met...
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Count occurrences of a char in plain text file

... answered Oct 21 '09 at 21:37 CascabelCascabel 398k6464 gold badges352352 silver badges307307 bronze badges ...
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What does “fragment” mean in ANTLR?

... 113 A fragment is somewhat akin to an inline function: It makes the grammar more readable and easier...
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Numpy first occurrence of value greater than existing value

...nce are returned.") and doesn't save another list. In [2]: N = 10000 In [3]: aa = np.arange(-N,N) In [4]: timeit np.argmax(aa>N/2) 100000 loops, best of 3: 52.3 us per loop In [5]: timeit np.where(aa>N/2)[0][0] 10000 loops, best of 3: 141 us per loop In [6]: timeit np.nonzero(aa>N/2)[0...
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How to check if a value exists in a dictionary (python)

... 394 >>> d = {'1': 'one', '3': 'three', '2': 'two', '5': 'five', '4': 'four'} >>>...
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Given an array of numbers, return array of products of all other numbers (no division)

... 1, a[0], a[0]*a[1], a[0]*a[1]*a[2], } { a[1]*a[2]*a[3], a[2]*a[3], a[3], 1, } Both of which can be done in O(n) by starting at the left and right edges respectively. Then multiplying the two arrays element by element gives the required result My...