大约有 48,000 项符合查询结果(耗时:0.0303秒) [XML]

https://stackoverflow.com/ques... 

dropping infinite values from dataframes in pandas?

...nf, -np.inf]) In [12]: df.replace([np.inf, -np.inf], np.nan) Out[12]: 0 0 1 1 2 2 NaN 3 NaN The same method would work for a Series. share | improve this answer | ...
https://stackoverflow.com/ques... 

How to determine the longest increasing subsequence using dynamic programming?

... 407 OK, I will describe first the simplest solution which is O(N^2), where N is the size of the col...
https://stackoverflow.com/ques... 

How to round a number to significant figures in Python

... 20 Answers 20 Active ...
https://stackoverflow.com/ques... 

How do I get indices of N maximum values in a NumPy array?

... | edited Aug 2 '11 at 10:45 answered Aug 2 '11 at 10:32 ...
https://stackoverflow.com/ques... 

Converting numpy dtypes to native python types

...py as np # for example, numpy.float32 -> python float val = np.float32(0) pyval = val.item() print(type(pyval)) # <class 'float'> # and similar... type(np.float64(0).item()) # <class 'float'> type(np.uint32(0).item()) # <class 'long'> type(np.int16(0).item()) # <...
https://stackoverflow.com/ques... 

How does numpy.histogram() work?

...qual width) of each bar. In this example: np.histogram([1, 2, 1], bins=[0, 1, 2, 3]) There are 3 bins, for values ranging from 0 to 1 (excl 1.), 1 to 2 (excl. 2) and 2 to 3 (incl. 3), respectively. The way Numpy defines these bins if by giving a list of delimiters ([0, 1, 2, 3]) in this example...
https://stackoverflow.com/ques... 

Why is SSE scalar sqrt(x) slower than rsqrt(x) * x?

... | edited Oct 7 '09 at 0:02 answered Oct 6 '09 at 23:52 ...
https://stackoverflow.com/ques... 

Change select box option background color

... 10 Answers 10 Active ...
https://stackoverflow.com/ques... 

How can I create a two dimensional array in JavaScript?

... 50 Answers 50 Active ...
https://stackoverflow.com/ques... 

Is R's apply family more than syntactic sugar?

... n < 2 ) n + else fibo(n-1) + fibo(n-2) + } > system.time(for(i in 0:26) fibo(i)) user system elapsed 7.48 0.00 7.52 > system.time(sapply(0:26, fibo)) user system elapsed 7.50 0.00 7.54 > system.time(lapply(0:26, fibo)) user system elapsed 7.48 ...