大约有 2,000 项符合查询结果（耗时：0.0252秒） [XML]
创业公司如何实施敏捷开发 - 资讯 - 清泛网 - 专注C/C++及内核技术
...始我们两个开发，这个时候只要两个人就能够很好的合作把产品开发出来，不需要什么模式。随着人员的扩充，团队间如何协作按时按质按量完成任务就需要好好思考下了。
尝试一，传统软件开发模式。整个过程为 需求分析、...
How to extract the n-th elements from a list of tuples?
...
This also works:
zip(*elements)[1]
(I am mainly posting this, to prove to myself that I have groked zip...)
See it in action:
>>> help(zip)
Help on built-in function zip in module builtin:
zip(...)
zip(seq1 [, seq2...
How to run functions in parallel?
...both to finish at critical synchronization points using Process.join like @aix's answer mentions.
This is better than time.sleep(10) because you can't guarantee exact timings. With explicitly waiting, you're saying that the functions must be done executing that step before moving to the next, inst...
Socket send函数和recv函数详解以及利用select()函数来进行指定时间的阻塞 ...
... 是否正在发送s的发送缓冲中的数据，如果是就等待协议把数据发送完，如果协议还没有开始发送s的发送缓冲中的数据或者s的发送缓冲中没有数据，那么 send就比较s的发送缓冲区的剩余空间和len，如果len大于剩余空间大小send就...
How to import CSV file data into a PostgreSQL table?
...t article.
Solution paraphrased here:
Create your table:
CREATE TABLE zip_codes
(ZIP char(5), LATITUDE double precision, LONGITUDE double precision,
CITY varchar, STATE char(2), COUNTY varchar, ZIP_CLASS varchar);
Copy data from your CSV file to the table:
COPY zip_codes FROM '/path/to/csv...
Add SUM of values of two LISTS into new LIST
...
The zip function is useful here, used with a list comprehension.
[x + y for x, y in zip(first, second)]
If you have a list of lists (instead of just two lists):
lists_of_lists = [[1, 2, 3], [4, 5, 6]]
[sum(x) for x in zip(*li...
淘宝大秒系统设计详解 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...宝详情上的定时上架功能，由于有些卖家为了吸引眼球，把价格压得很低。但这给的详情系统带来了很大压力，为了将这种突发流量隔离，才设计了秒杀系统，文章主要介绍大秒系统以及这种典型读数据的热点问题的解决思路和...
How do I zip two arrays in JavaScript? [duplicate]
...otype.map()
const a = [1, 2, 3],
b = ['a', 'b', 'c'];
const zip = (arr1, arr2) => arr1.map((k, i) => [k, arr2[i]]);
console.log(zip(a, b)) // [[1, "a"], [2, "b"], [3, "c"]]
Using for loop
var a = [1, 2, 3],
b = ['a', 'b', 'c'];
var zip = [];
for (var i = ...
Finding differences between elements of a list
...
>>> t
[1, 3, 6]
>>> [j-i for i, j in zip(t[:-1], t[1:])] # or use itertools.izip in py2k
[2, 3]
share
|
improve this answer
|
follow
...
Where to find Java JDK Source Code? [closed]
... So I want the JDK Source Code.
Before I re-installed Linux I had the src.zip package with all the official source code in it. I just had to tell Eclipse where this file is and I could see the code. But now I don't have the file anymore...
...