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How do I overload the [] operator in C# [duplicate]

...t every time I need to implement an index operator, I have to look it up? And each time I end up on this answer... wish I could vote it up multiple times :) – DSO Dec 31 '11 at 0:52 ...
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How to modify the keyboard shortcuts in Eclipse IDE?

...rences > General > Keys In particular, edit the "Run Ant Build" command. share | improve this answer | follow | ...
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Java split() method strips empty strings at the end? [duplicate]

...Word + "'"); } } return l; } returns 'a' and ' '. Whereas, if String s = "a a"; then output is just 'a' followed by another 'a' Why is this happening in Java 8? – sofs1 Feb 1 '19 at 23:06 ...
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Is there a Wikipedia API?

...Wikipedia (docs). You can also use the Special:Export feature to dump data and parse it yourself. More information. share answered Mar 9 '09 at 19:08 ...
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What's the regular expression that matches a square bracket?

...May 29 '09 at 20:51 Peter StuifzandPeter Stuifzand 4,66511 gold badge2020 silver badges2828 bronze badges ...
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Invalid syntax when using “print”? [duplicate]

I'm learning Python and can't even write the first example: 4 Answers 4 ...
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Global variables in R

...;<- will search up the chain of enclosures up to the global environment and assign to the first matching variable it finds. Hypothetically, if you have a function f() nested in a closure g() and a exists in g(), then using a <<- in f() will assign to a in g(), not to the global environment....
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Printing Python version in output

...Léonard's solution is the best. You might want to examine the full string and see if you need it or portions of it. share | improve this answer | follow | ...
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How do I pick 2 random items from a Python set? [duplicate]

... Use the random module: http://docs.python.org/library/random.html import random random.sample(set([1, 2, 3, 4, 5, 6]), 2) This samples the two values without replacement (so the two values are different). ...
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Converting an array to a function arguments list [duplicate]

... current versions of JS you can use: app[func]( ...args ); Users of ES5 and older will need to use the .apply() method: app[func].apply( this, args ); Read up on these methods at MDN: .apply() spread "..." operator (not to be confused with the related rest "..." parameters operator: it's go...