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LINQ equivalent o<em>fem> <em>fem>or<em>eacem>h <em>fem>or IEnumerable
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880
There is no <em>Fem>or<em>Eacem>h extension <em>fem>or IEnumerable; only <em>fem>or List<T>. So you could do
items....
python: SyntaxError: EOL while scanning string literal
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93
I had this problem - I eventually worked out that the reason was that I'd included \ characters...
How to get current memory usage in android?
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sarnoldsarnold
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Custom HTTP headers : naming conventions
...he best convention is to use the a<em>fem>orementioned "X-ACME-ClientData". "X-" <em>bcem> it's not standard (nor will it ever be, which is why the IET<em>Fem> deprecation is moot here), "ACME-" to namespace it to your "ACME" company or speci<em>fem>ic app, and "ClientData" can be whatever semantic name you like. :)
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Converting a column within pandas data<em>fem>rame <em>fem>rom int to string
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cs95
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answered Jul 30 '13 at 14:59
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How do I get a TextBox to only accept numeric input in WP<em>Fem>?
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I used some o<em>fem> what was already here and put my own twist on it using a behavior so I don't hav...
Random data in Unit Tests?
...test the algorithm. You can read some o<em>fem> this online at Google Books, page 95, but it's a great book worth having.
So basically this just shows that generating random data <em>fem>or testing is a viable option.
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Any reason why scala does not explicitly support dependent types?
...ss Bar }
de<em>fem>ined class <em>Fem>oo
scala> val <em>fem>oo1 = new <em>Fem>oo
<em>fem>oo1: <em>Fem>oo = <em>Fem>oo@24<em>bcem>0658
scala> val <em>fem>oo2 = new <em>Fem>oo
<em>fem>oo2: <em>Fem>oo = <em>Fem>oo@6<em>fem>7<em>fem>757
scala> implicitly[<em>fem>oo1.Bar =:= <em>fem>oo1.Bar] // OK: equal types
res0: =:=[<em>fem>oo1.Bar,<em>fem>oo1.Bar] = <<em>fem>unction1>
scala> implicitly[<em>fem>oo1.Bar =:= <em>fem>oo2.Bar] // Not...
How to determine the current shell I'm working on
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${.sh.version} is set on ksh93
– <em>fem>pmurphy
Jul 24 '10 at 22:20
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In c# what does 'where T : class' mean?
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Vilx-Vilx-
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