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How to output numbers with leading zeros in JavaScript [duplicate]
... a way to round left of the decimal? for example 5 becomes 05 if I specify 2 places
6 Answers
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@RequestParam vs @PathVariable
...URI (Spring call it an URI Template)
— see Spring Reference Chapter 16.3.2.2 URI Template Patterns
@RequestParam is to obtain a parameter from the URI as well — see Spring Reference Chapter 16.3.3.3 Binding request parameters to method parameters with @RequestParam
If the URL http://localhost:...
How can I count the occurrences of a list item?
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25 Answers
25
Active
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How to use sed to remove the last n lines of a file
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22 Answers
22
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iTerm 2: How to set keyboard shortcuts to jump to beginning/end of line?
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Add in iTerm2 the following Profile Shortcut Keys
FOR ACTION SEND
⌘← "SEND HEX CODE" 0x01
⌘→ "SEND HEX CODE" 0x05
⌥← "SEND ESC SEQ" b
⌥→ "SEND ESC SEQ" f
Here is a visual for those who need it...
In practice, what are the main uses for the new “yield from” syntax in Python 3.3?
...nd preclude a whole bunch of new features from being implemented in Python 2.x.
What yield from does is it establishes a transparent bidirectional connection between the caller and the sub-generator:
The connection is "transparent" in the sense that it will propagate everything correctly too, not...
What's the difference between Sender, From and Return-Path?
...y round?
– Ethan Leroy
Feb 6 '15 at 22:03
7
Imagine some VIP that has an assistant managing their...
Need for predictable random generator
...loper and I got a problem with random numbers. Let's say that a player has 20% chance to get a critical hit with his sword. That means, 1 out of 5 hits should be critical. The problem is I got very bad real life results — sometimes players get 3 crits in 5 hits, sometimes none in 15 hits. Battles ...
How to calculate the number of days between two dates? [duplicate]
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const oneDay = 24 * 60 * 60 * 1000; // hours*minutes*seconds*milliseconds
const firstDate = new Date(2008, 1, 12);
const secondDate = new Date(2008, 1, 22);
const diffDays = Math.round(Math.abs((firstDate - secondDate) / oneDay));
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