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Undefined method 'task' using Rake 0.9.0
I just updated Rake to the latest version ( 0.9.0.beta.4 ) and the rake command ends up with the following error message:
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How to wait in bash for several subprocesses to finish and return exit code !=0 when any subprocess
...ral subprocesses spawned from that script to finish and return exit code !=0 when any of the subprocesses ends with code !=0 ?
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Value of i for (i == -i && i != 0) to return true in Java
....toBinaryString(Integer.MIN_VALUE));
you see that Integer.MIN_VALUE is
10000000000000000000000000000000
Taking the negative value is done by first swapping 0 and 1, which gives
01111111111111111111111111111111
and by adding 1, which gives
10000000000000000000000000000000
As you can see in...
typedef fixed length array
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answered Dec 24 '10 at 0:44
R.. GitHub STOP HELPING ICER.. GitHub STOP HELPING ICE
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Have a fixed position div that needs to scroll if content overflows
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The problem with using height:100% is that it will be 100% of the page instead of 100% of the window (as you would probably expect it to be). This will cause the problem that you're seeing, because the non-fixed content is long enough to include the fixed ...
Javascript swap array elements
... = list[y];
list[y] = list[x];
list[x] = b;
Edit hijacking top answer 10 years later with a lot of ES6 adoption under our belts:
Given the array arr = [1,2,3,4], you can swap values in one line now like so:
[arr[0], arr[1]] = [arr[1], arr[0]];
This would produce the array [2,1,3,4]. This is ...
What's Go's equivalent of argv[0]?
...t my own program's name at runtime? What's Go's equivalent of C/C++'s argv[0]? To me it is useful to generate the usage with the right name.
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Select random row from a sqlite table
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answered Feb 17 '10 at 10:06
Adriaan StanderAdriaan Stander
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Creating dataframe from a dictionary where entries have different lengths
Say I have a dictionary with 10 key-value pairs. Each entry holds a numpy array. However, the length of the array is not the same for all of them.
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What is the difference between & and && in Java?
...the first operand evaluates to false since the result will be false
(x != 0) & (1/x > 1) <-- this means evaluate (x != 0) then evaluate (1/x > 1) then do the &. the problem is that for x=0 this will throw an exception.
(x != 0) && (1/x > 1) <-- this means evaluate (x...