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List comprehension vs. lambda + filter

... list comprehension only accesses local variables. If you are using Python 3.x the list comprehension runs in a separate function so it will also be accessing value through a closure and this difference won't apply. The other option to consider is to use a generator instead of a list comprehension:...
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Unit testing of private methods [duplicate]

... answered Sep 9 '10 at 12:53 Mike SeymourMike Seymour 230k2424 gold badges396396 silver badges602602 bronze badges ...
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Why java.io.File doesn't have a close() method?

... answered Jan 20 '11 at 20:37 biziclopbiziclop 45.2k1212 gold badges7070 silver badges9696 bronze badges ...
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vs2008编译boost详细步骤 - 开源 & Github - 清泛网 - 专注C/C++及内核技术

... (2)Spirit,LL parser framework,用C++代码直接表达EBNF; (3)Graph,图组件和算法; (4)Lambda,在调用的地方定义短小匿名的函数对象,很实用的functional功能; (5)concept check,检查泛型编程中的concept; (6)Mpl,用模板实现...
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Simple example of threading in C++

... user276648 4,83355 gold badges4747 silver badges7979 bronze badges answered Jun 27 '12 at 15:31 MasterMasticMasterM...
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How do I create a SHA1 hash in ruby?

... 386 require 'digest/sha1' Digest::SHA1.hexdigest 'foo' ...
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How to convert image to byte array

... Pranay RanaPranay Rana 159k3333 gold badges218218 silver badges248248 bronze badges ...
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Regular expression for a string containing one word but not another

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What's the safest way to iterate through the keys of a Perl hash?

... answered Aug 6 '08 at 13:22 John SiracusaJohn Siracusa 14k66 gold badges3939 silver badges5353 bronze badges ...
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Return two and more values from a method

... def sumdiff(x, y) return x+y, x-y end #=> nil sumdiff(3, 4) #=> [7, -1] a = sumdiff(3,4) #=> [7, -1] a #=> [7, -1] a,b=sumdiff(3,4) #=> [7, -1] a #=> 7 b #=> -1 a,b,c=sumdiff(3,4) #=> [7, -1] a #=> 7 b #=> -1 c #=> nil ...