大约有 47,000 项符合查询结果（耗时：0.0653秒） [XML]
How to determine whether a Pandas Column contains a particular value
...s in the index:
In [11]: s = pd.Series(list('abc'))
In [12]: s
Out[12]:
0 a
1 b
2 c
dtype: object
In [13]: 1 in s
Out[13]: True
In [14]: 'a' in s
Out[14]: False
One option is to see if it's in unique values:
In [21]: s.unique()
Out[21]: array(['a', 'b', 'c'], dtype=object)
In [22]:...
.NET 4.0 build issues on CI server
Anybody manage to get .NET 4.0 applications compiling on a CI server without installing Visual Studio 2010 on a CI server?
...
Change text color of one word in a TextView
...e html.
String first = "This word is ";
String next = "<font color='#EE0000'>red</font>";
t.setText(Html.fromHtml(first + next));
But this will require you to rebuild the TextView when (if?) you want to change the color, which could cause a hassle.
...
super() fails with error: TypeError “argument 1 must be type, not classobj” when parent does not inh
...
answered Nov 11 '09 at 4:40
stevehasteveha
64.4k1616 gold badges8181 silver badges109109 bronze badges
...
Sort array of objects by string property value
...
4103
It's easy enough to write your own comparison function:
function compare( a, b ) {
if ( a.la...
How do I sort an array of hashes by a value in the hash?
...
Nowaker
10.7k44 gold badges4545 silver badges5959 bronze badges
answered Jun 30 '10 at 23:29
Stéphan KochenSt...
Calculate relative time in C#
...
1005
Jeff, your code is nice but could be clearer with constants (as suggested in Code Complete).
...
How to use QueryPerformanceCounter?
...
#include <windows.h>
double PCFreq = 0.0;
__int64 CounterStart = 0;
void StartCounter()
{
LARGE_INTEGER li;
if(!QueryPerformanceFrequency(&li))
cout << "QueryPerformanceFrequency failed!\n";
PCFreq = double(li.QuadPart)/1000.0;
Q...
How is set() implemented?
... AJP
19.9k1616 gold badges7272 silver badges102102 bronze badges
answered Oct 16 '10 at 14:47
Justin EthierJustin Ethier
11...
MySQL - Get row number on select
...
Take a look at this.
Change your query to:
SET @rank=0;
SELECT @rank:=@rank+1 AS rank, itemID, COUNT(*) as ordercount
FROM orders
GROUP BY itemID
ORDER BY ordercount DESC;
SELECT @rank;
The last select is your count.
...