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Code Golf: Lasers
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Perl, 166 160 characters
Perl, 251 248 246 222 214 208 203 201 193 190 180 176 173 170 166 --> 160 chars.
Solution had 166 strokes when this contest ended, but A. Rex has found a couple ways to shave off 6 more characters:
s!.!$t{...
Does MSTest have an equivalent to NUnit's TestCase?
... note on an older version of the TestAdapter, which was removed from the 2.0.0's description page:
Note that it doesn't work with VS Express
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Accessing nested JavaScript objects and arays by string path
... // strip a leading dot
var a = s.split('.');
for (var i = 0, n = a.length; i < n; ++i) {
var k = a[i];
if (k in o) {
o = o[k];
} else {
return;
}
}
return o;
}
Usage::
Object.byString(someObj, 'part3[0].name');
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Simple (non-secure) hash function for JavaScript? [duplicate]
...numerical hash code (more specifically, a Java equivalent) such as 1395333309.
String.prototype.hashCode = function() {
var hash = 0;
if (this.length == 0) {
return hash;
}
for (var i = 0; i < this.length; i++) {
var char = this.charCodeAt(i);
hash = ((ha...
Is a Python list guaranteed to have its elements stay in the order they are inserted in?
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answered Dec 4 '12 at 0:11
sgesge
5,95011 gold badge1212 silver badges1616 bronze badges
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How to iterate a loop with index and element in Swift
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Yes. As of Swift 3.0, if you need the index for each element along with its value, you can use the enumerated() method to iterate over the array. It returns a sequence of pairs composed of the index and the value for each item in the array. For...
Example of Named Pipes
...tring[] args)
{
StartServer();
Task.Delay(1000).Wait();
//Client
var client = new NamedPipeClientStream("PipesOfPiece");
client.Connect();
StreamReader reader = new StreamReader(client);
StreamWriter writer...
Height equal to dynamic width (CSS fluid layout) [duplicate]
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edited Dec 5 '14 at 16:05
chridam
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answe...
How can I check if character in a string is a letter? (Python)
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AMC
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answered Mar 21 '13 at 21:24
rainerrainer
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Iterating over a numpy array
...>>> for (x,y), value in numpy.ndenumerate(a):
... print x,y
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0 0
0 1
1 0
1 1
2 0
2 1
Regarding the performance. It is a bit slower than a list comprehension.
X = np.zeros((100, 100, 100))
%timeit list([((i,j,k), X[i,j,k]) for i in range(X.shape[0]) for j in range(X.shape[1]) for k...