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Is “double hashing” a password less secure than just hashing it once?
... a password twice before storage any more or less secure than just hashing it once?
16 Answers
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When NOT to call super() method when overriding?
When I make my own Android custom class, I extend its native class. Then when I want to override the base method, I always call super() method, just like I always do in onCreate , onStop , etc.
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Secure Web Services: REST over HTTPS vs SOAP + WS-Security. Which is better? [closed]
I'm not a security expert by any means, but I favor creating REST-style web services.
11 Answers
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Variable declared in for-loop is local variable?
I have been using C# for quite a long time but never realised the following:
9 Answers
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What do people think of the fossil DVCS? [closed]
... http://www.fossil-scm.org
I found this recently and have started using it for my home projects. I want to hear what other people think of this VCS.
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Add Keypair to existing EC2 instance
I was given AWS Console access to an account with 2 instances running that I cannot shut down (in production). I would however like to gain SSH access to these instances, is it possible to create a new Keypair and apply it to the instances so I can SSH in? Obtaining the exisiting pem file for the ke...
How can I tell when HttpClient has timed out?
As far as I can tell, there's no way to know that it's specifically a timeout that has occurred. Am I not looking in the right place, or am I missing something bigger?
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When to use reinterpret_cast?
I am little confused with the applicability of reinterpret_cast vs static_cast . From what I have read the general rules are to use static cast when the types can be interpreted at compile time hence the word static . This is the cast the C++ compiler uses internally for implicit casts also.
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Static variable inside of a function in C
...nside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the life...
Why does Hibernate require no argument constructor?
... no-arg constructor, since serialization uses jvm magic to create objects without invoking the constructor. But this is not available across all VMs. For example, XStream can create instances of objects that don't have a public no-arg constructor, but only by running in a so-called "enhanced" mode w...