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Calling closure assigned to object property directly
...e for StdClass of course, because you cannot add the __call method)
class Foo
{
public function __call($method, $args)
{
if(is_callable(array($this, $method))) {
return call_user_func_array($this->$method, $args);
}
// else throw exception
}
}
$fo...
Convert file path to a file URI?
...e paths. So you can just do the following:
var uri = new System.Uri("c:\\foo");
var converted = uri.AbsoluteUri;
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Why is using “for…in” for array iteration a bad idea?
...ate:
// Somewhere deep in your JavaScript library...
Array.prototype.foo = 1;
// Now you have no idea what the below code will do.
var a = [1, 2, 3, 4, 5];
for (var x in a){
// Now foo is a part of EVERY array and
// will show up here as a value of 'x'.
console.log(x);
}
...
PHP 5: const vs static
...nction) and can store its value between function calls, example:
function foo()
{
static $numOfCalls = 0;
$numOfCalls++;
print("this function has been executed " . $numOfCalls . " times");
}
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Performance difference for control structures 'for' and 'foreach' in C#
...Time.Now;
for (int i = 0; i < intList.Count; i++)
{
int foo = intList[i] * 2;
if (foo % 2 == 0)
{
}
}
TimeSpan finished = DateTime.Now - timeStarted;
Console.WriteLine(finished.TotalMilliseconds.ToString());
Console.Read();
}
And here i...
git ignore exception
...avior I want. However, if I want an exception ( i.e. to be able to commit foo.dll ), how can I achieve this?
9 Answers
...
JavaScript closures vs. anonymous functions
....
Consider the following example;
function f()
{//begin of scope f
var foo='hello'; //foo is declared in scope f
for(var i=0;i<2;i++){//i is declared in scope f
//the for loop is not a function, therefore we are still in scope f
var bar = 'Am I accessible?';//bar is declared in sc...
To underscore or to not to underscore, that is the question
...rk languages? For example since C# is case-sensitive you can call a field "foo" and the public property "Foo" and it works fine.
...
Can virtual functions have default parameters?
...er values are based on the static type.
Given
class A {
virtual void foo(int i = 1) { cout << "A::foo" << i << endl; }
};
class B: public A {
virtual void foo(int i = 2) { cout << "B::foo" << i << endl; }
};
void test() {
A a;
B b;
A* ap = &b;
a.foo(...
Any reason not to use '+' to concatenate two strings?
...ires an argument, and you write it expecting to get a string:
In [1]: def foo(zeta):
...: print 'bar: ' + zeta
In [2]: foo('bang')
bar: bang
So, this function may be used pretty often throughout the code. Your coworkers may know exactly what it does, but not necessarily be fully up-to-sp...