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How to insert values into C# Dictionary on instantiation?
...Dictionary when I create it? I can, but don't want to, do
dict.Add(int, "string") for each item if there is something more efficient like:
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How to declare a type as nullable in TypeScript?
...ptional which is different from nullable.
interface Employee1 {
name: string;
salary: number;
}
var a: Employee1 = { name: 'Bob', salary: 40000 }; // OK
var b: Employee1 = { name: 'Bob' }; // Not OK, you must have 'salary'
var c: Employee1 = { name: 'Bob', salary: undefined }; // OK
var d:...
How to strip all non-alphabetic characters from string in SQL Server?
How could you remove all characters that are not alphabetic from a string?
18 Answers
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converting CSV/XLS to JSON? [closed]
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Extra credit: save json to a file... $topicsjson | Add-Content -Path "mydata.json"
– brady321
Apr 10 '18 at 19:46
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How can I convert a comma-separated string to an array?
I have a comma-separated string that I want to convert into an array, so I can loop through it.
15 Answers
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Combining “LIKE” and “IN” for SQL Server [duplicate]
...ple if your text was 'Hello World' it would find two matches and create an extra row in the results. The first line should be SELECT DISTINCT t.* to avoid this happening.
– Dave Sexton
Nov 16 '15 at 9:55
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@Scope(“prototype”) bean scope not creating new bean
...nd value of the @Scope annotation.
With this trick you can avoid to write extra code or to inject the ApplicationContext every time that you need a prototype inside a singleton bean.
Example:
@Service
@Scope(value="prototype", proxyMode=ScopedProxyMode.TARGET_CLASS)
public class LoginAction {}...
Do I have to Close() a SQLConnection before it gets disposed?
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The using keyword will close the connection correctly so the extra call to Close is not required.
From the MSDN article on SQL Server Connection Pooling:
"We strongly recommend that you always
close the connection when you are
finished using it so that the
connection will be...
Search text in stored procedure in SQL Server
...ike '%\[ABD\]%' ESCAPE '\'
Then the square brackets will be treated as a string literals not as wild cards.
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Deserializing JSON data to C# using JSON.NET
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Use
var rootObject = JsonConvert.DeserializeObject<RootObject>(string json);
Create your classes on JSON 2 C#
Json.NET documentation: Serializing and Deserializing JSON with Json.NET
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