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Failed binder transaction when putting an bitmap dynamically in a widget
...ten to local storage and then prefetched or what? Can I possibly lose data if I add more pages?
– G_V
Dec 3 '14 at 8:18
7
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iOS: How to get a proper Month name from a number?
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Simplification: NSString *monthName = [[[NSDateFormatter alloc] init] monthSymbols][monthNumber-1];
– Johannes Fahrenkrug
Jun 4 '13 at 11:23
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Using [UIColor colorWithRed:green:blue:alpha:] doesn't work with UITableView seperatorColor?
...:(green/255.0) blue:(blue/255.0) alpha:alpha];
}
@end
So you can just do(If you import the category I linked to above):
[UIColor colorWithR:127 G:127: B:127 A:1];
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SpeechRecognizer 语音识别扩展：获取设备支持的语音识别语言列表 · App I...
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下载
.aix拓展文件：
com.puravidaapps.TaifunSpeechRecognizer.aix
.aia示例文件：
speech.aia
版本历史
版本
日期
修改内容
1
2016-11-05
初始版本
2...
Error 1103: Unable to complete the given request · App Inventor 2 中文网
...d=9fd2eba4-b84e-4db7-8442-d956c741728e&r2=true&useproxy=true"
with the specified URL: http://rendezvous.appinventor.mit.edu/rendezvous/
原因
AI2 伴侣无法接入互联网导致请求失败。可能网络权限没开，可能手机安全软件把它网络限制了。可...
How to Pass Parameters to Activator.CreateInstance()
I want to create an instance of a type that I specify in a generic method that I have. This type has a number of overloaded constructors. I'd like to be able to pass arguments to the constructors, but
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StringUtils 字符串工具扩展：强大的文本处理工具集 · App Inventor 2 中文网
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当前包可直接验证文本是否为空：
when 按钮1.Click() {
if UrsAI2StringUtils1.IsEmptyOf(文本输入框1.Text) {
对话框1.ShowAlert("请输入邮箱地址")
} else {
对话框1.ShowAlert("已填写邮箱地址；邮箱格式请在新版扩展中用 isEmailOf 校验")
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DataTable: Hide the Show Entries dropdown but keep the Search box
...bInfo": false,
"bAutoWidth": false });
});
Hope that helps !
EDIT : If you are lazy, "bLengthChange": false, is the one you need to change :)
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compilation warning: no rule to process file for architecture i386
...phases (when it's not supposed to) because the .m file has (by mistake) a different name.
– Ali
Oct 11 '13 at 15:07
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How to get row from R data.frame
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If you don't know the row number, but do know some values then you can use subset
x <- structure(list(A = c(5, 3.5, 3.25, 4.25, 1.5 ),
B = c(4.25, 4, 4, 4.5, 4.5 ),
C = ...