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How is an overloaded method chosen when a parameter is the literal null value?
...("Hello methodC");
}
}
public class MyTest {
public static void fun(B Obj){
System.out.println("B Class.");
}
public static void fun(A Obj){
System.out.println("A Class.");
}
public static void main(String[] args) {
fun(null);
}
}
output...
How to check if an object is a list or tuple (but not string)?
... tuple - but not a str . Because many times I stumbled upon bugs where a function passes a str object by mistake, and the target function does for x in lst assuming that lst is actually a list or tuple .
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std::function vs template
Thanks to C++11 we received the std::function family of functor wrappers. Unfortunately, I keep hearing only bad things about these new additions. The most popular is that they are horribly slow. I tested it and they truly suck in comparison with templates.
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Truncate (not round) decimal places in SQL Server
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select round(123.456, 2, 1)
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How to remove text from a string?
I've got a data-123 string.
11 Answers
11
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Validate phone number with JavaScript
...fectly. It validates that the phone number is in one of these formats:
(123) 456-7890 or 123-456-7890
26 Answers
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How to disable copy/paste from/to EditText
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I am able to disable copy-and-paste functionality with the following:
textField.setCustomSelectionActionModeCallback(new ActionMode.Callback() {
public boolean onCreateActionMode(ActionMode actionMode, Menu menu) {
return false;
}
public ...
boost Composite keys - C/C++ - 清泛网 - 专注C/C++及内核技术
...lly taken care of: boost::hash is specialized to hash a composite key as a function of the boost::hash values of its elements. Should we need to specify different hash functions for the elements of a composite key, we can explicitly do so by using the composite_key_hash utility:
struct tuned_i...
Understanding the map function
Apply function to every item of iterable and return a list of the results. If additional iterable arguments are passed, function must take that many arguments and is applied to the items from all iterables in parallel.
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Python's equivalent of && (logical-and) in an if-statement
...lt, then the second operator isn't evaluated at all.
To show this I use a function that simply takes a value, prints it and returns it again. This is handy to see what is actually
evaluated because of the print statements:
>>> def print_and_return(value):
... print(value)
... retu...