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Remove all spaces from a string in SQL Server
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Simply replace it;
SELECT REPLACE(fld_or_variable, ' ', '')
Edit:
Just to clarify; its a global replace, there is no need to trim() or worry about multiple spaces for either char or varchar:
create table #t (
c char(8),
v varchar(8))...
Quick Way to Implement Dictionary in C
...mp;matF },
};
mat* getMat(char * str)
{
stringToMat* pCase;
mat * selected = NULL;
if (str != NULL)
{
/* runing on the dictionary to get the mat selected */
for(pCase = matCases; pCase != matCases + sizeof(matCases) / sizeof(matCases[0]); pCase++ )
{
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Is SQL or even TSQL Turing Complete?
...(0);
-- Initialization of temporary variables
DECLARE @CodeLength INT = (SELECT COUNT(*) FROM @CodeTable);
DECLARE @CodeIndex INT = 0;
DECLARE @Pointer INT = 1;
DECLARE @InputIndex INT = 0;
DECLARE @Command CHAR(1);
DECLARE @Depth INT;
-- Main calculation cycle
WHILE @CodeIndex < @...
Pad a string with leading zeros so it's 3 characters long in SQL Server 2008
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If the field is already a string, this will work
SELECT RIGHT('000'+ISNULL(field,''),3)
If you want nulls to show as '000'
It might be an integer -- then you would want
SELECT RIGHT('000'+CAST(field AS VARCHAR(3)),3)
As required by the question this answer only w...
Formatting Numbers by padding with leading zeros in SQL Server
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Change the number 6 to whatever your total length needs to be:
SELECT REPLICATE('0',6-LEN(EmployeeId)) + EmployeeId
If the column is an INT, you can use RTRIM to implicitly convert it to a VARCHAR
SELECT REPLICATE('0',6-LEN(RTRIM(EmployeeId))) + RTRIM(EmployeeId)
And the code to re...
MySQL - How to select data by string length
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select LENGTH('Ö'); results 2!! András Szepesházi's answer is the correct one!
– fubo
Oct 24 '13 at 13:59
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How do you create a random string that's suitable for a session ID in PostgreSQL?
...sion verification using PostgreSQL. I know I can get a random number with SELECT random() , so I tried SELECT md5(random()) , but that doesn't work. How can I do this?
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What's the difference between VARCHAR and CHAR?
...CHAR(10),
Street VARCHAR(10));
Insert into temp
values('Pune','Oxford');
select length(city), length(street) from temp;
Output will be
length(City) Length(street)
10 6
Conclusion: To use storage space efficiently must use VARCHAR Instead CHAR if variable length is ...
How to convert int to char with leading zeros?
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Try this: select right('00000' + cast(Your_Field as varchar(5)), 5)
It will get the result in 5 digits, ex: 00001,...., 01234
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VC DDE（Dynamic Data Exchange）与EXCEL连接 - C/C++ - 清泛网 - 专注C/C++及内核技术
...char szItem5[] = "R3C1"; char szData5[16] = "0";
//char szCmd2[] = "[SELECT(\"R3C1\")][FONT.PROPERTIES(,\"Bold\")][SAVE()][QUIT()]";
char szCmd2[] = "[SELECT(\"R3C1\")][FONT.PROPERTIES(,\"Bold\")]";
char szCmd3[] = "[SELECT(\"R3C1\")][FONT.PROPERTIES(,\"Bold\")]";
int i,j,k;
char...