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Convert floating point number to a certain precision, and then copy to string
I have a floating point number, say 135.12345678910 . I want to concatenate that value to a string, but only want 135.123456789 . With print, I can easily do this by doing something like:
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Easy pretty printing of floats in python?
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answered May 3 '18 at 11:37
PlasmaBinturongPlasmaBinturong
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What does the plus sign do in '+new Date'
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dovid
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answered Oct 21 '08 at 11:49
kentaromiurakentaromi...
Disable Maven warning message - “Selected war files include a WEB-INF/web.xml which will be ignored”
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How do I change the IntelliJ IDEA default JDK?
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283
This setting is changed in the "Default Project Structure..." dialog. Navigate to "File" -> ...
Prevent ViewPager from destroying off-screen views
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what is “strict mode” and how is it used?
...rict"; at the top of your code, before anything else.
For example, blah = 33; is valid JavaScript. It means you create a completely global variable blah.
But in strict mode its an error because you did not use the keyword "var" to declare the variable.
Most of the time you don't mean to create gl...
Output array to CSV in Ruby
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To a file:
require 'csv'
CSV.open("myfile.csv", "w") do |csv|
csv << ["row", "of", "C...
How to convert int to char with leading zeros?
...as varchar(5)), 5)
It will get the result in 5 digits, ex: 00001,...., 01234
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Python logging: use milliseconds in time format
...else:
t = time.strftime("%Y-%m-%d %H:%M:%S", ct)
s = "%s,%03d" % (t, record.msecs)
return s
Notice the comma in "%s,%03d". This can not be fixed by specifying a datefmt because ct is a time.struct_time and these objects do not record milliseconds.
If we change the definition ...