大约有 47,000 项符合查询结果（耗时：0.0627秒） [XML]
php中json_decode()和json_encode()的使用方法 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...de()和json_encode()的使用方法1.json_decode()json_decode(PHP 5 >= 5.2.0, PECL json >= 1.2.0)json_decode — 对 JSON 格式的字符串进行编码说明mixed jso...1.json_decode()
(PHP 5 >= 5.2.0, PECL json >= 1.2.0)
对 JSON 格式的字符串进行编码
说明：
mixed json_decode ...
str performance in python
...
105
'%s' % 100000 is evaluated by the compiler and is equivalent to a constant at run-time.
>&g...
ERROR: Error installing capybara-webkit:
...ou are on Mac
brew install qt
and then
gem install capybara-webkit -v '0.11.0'
share
|
improve this answer
|
follow
|
...
How to write a cron that will run a script every day at midnight?
...how to use it on Ubuntu. Your crontab line will look something like this:
00 00 * * * ruby path/to/your/script.rb
(00 00 indicates midnight--0 minutes and 0 hours--and the *s mean every day of every month.)
Syntax:
mm hh dd mt wd command
mm minute 0-59
hh hour 0-23
dd day of month 1-...
What does glLoadIdentity() do in OpenGL?
...lent of 1, is not exactly correct. The matrix actually looks like this:
1 0 0 0
0 1 0 0
0 0 1 0
0 0 0 1
That is the identity matrix. Boon is correct, mathematically, that any matrix multiplied with that matrix (or a matrix that looks like that; diagonal ones, all else 0s) will result in the origi...
Compare two DataFrames and output their differences side-by-side
... rows are empty*:
In [21]: ne = (df1 != df2).any(1)
In [22]: ne
Out[22]:
0 False
1 True
2 True
dtype: bool
Then we can see which entries have changed:
In [23]: ne_stacked = (df1 != df2).stack()
In [24]: changed = ne_stacked[ne_stacked]
In [25]: changed.index.names = ['id', 'col']
...
CSS I want a div to be on top of everything
...
dev.bv
93099 silver badges1616 bronze badges
answered Sep 14 '11 at 19:22
Skylar AndersonSkylar Anderson
...
Objective-C - Remove last character from string
...hat method you can trim your string like this:
if ([string length] > 0) {
string = [string substringToIndex:[string length] - 1];
} else {
//no characters to delete... attempting to do so will result in a crash
}
If you want a fancy way of doing this in just one line of code you...
Divide a number by 3 without using *, /, +, -, % operators
... x = t;
}
return y;
}
int divideby3(int num)
{
int sum = 0;
while (num > 3) {
sum = add(num >> 2, sum);
num = add(num >> 2, num & 3);
}
if (num == 3)
sum = add(sum, 1);
return sum;
}
As Jim commented this works, because:...
Logging framework incompatibility
...
You are mixing the 1.5.6 version of the jcl bridge with the 1.6.0 version of the slf4j-api; this won't work because of a few changes in 1.6.0. Use the same versions for both, i.e. 1.6.1 (the latest). I use the jcl-over-slf4j bridge all the time and it works fine.
...