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Bootstrap select dropdown list placeholder
... edited May 8 '18 at 17:08
Alexander Abakumov
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answered Aug 29 '14 at 11:04
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Is it possible to pass query parameters via Django's {% url %} template tag?
...d Jan 4 '11 at 7:51
Daniel RosemanDaniel Roseman
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send Content-Type: application/json post with node.js
...would we do this using 'http' module ? Thank you.
– Andrei Diaconescu
Jun 23 at 10:03
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LINQ Group By into a Dictionary Object
...okup(customObject => customObject);
Basically, it takes the IGrouping and materializes it for you into a dictionary of lists, with the values of PropertyName as the key.
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Check if item is in an array / list
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@jdi, and that loop will run much faster than the one coded explicitly in Python, not to mention being easier to read.
– Mark Ransom
Jun 28 '12 at 19:44
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Creating a constant Dictionary in C#
...return 1;
case "elephant": return 3;
}
This is exactly what you want. And yes, I know, it's ugly.
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How to find the installed pandas version
I am having trouble with some of pandas functionalities. How do I check what is my installation version?
6 Answers
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Is there a way to make a DIV unselectable?
...oft.com/en-us/library/hh801966(v=vs.85).aspx But I actually tested on IE, and it works correctly.
– KimKha
May 1 '13 at 15:27
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How do I get the function name inside a function in PHP?
...un 17 '09 at 10:33
PatrikAkerstrandPatrikAkerstrand
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UnicodeDecodeError: 'utf8' codec can't decode byte 0xa5 in position 0: invalid start byte
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The error is because there is some non-ascii character in the dictionary and it can't be encoded/decoded. One simple way to avoid this error is to encode such strings with encode() function as follows (if a is the string with non-ascii character):
a.encode('utf-8').strip()
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