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What is a lambda (function)?
For a person without a comp-sci background, what is a lambda in the world of Computer Science?
23 Answers
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The 3 different equals
What is the difference between = , == , and === ?
5 Answers
5
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How to find list intersection?
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If order is not important and you don't need to worry about duplicates then you can use set intersection:
>>> a = [1,2,3,4,5]
>>> b = [1,3,5,6]
>>> list(set(a) & set(b))
[1, 3, 5]
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Modulo operator with negative values [duplicate]
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From ISO14882:2011(e) 5.6-4:
The binary / operator yields the quotient, and the binary % operator
yields the remainder from the division of the first expression by the
second. If the second operand of / or % is zero the behavior is
undefined. For integ...
Is it possible to modify variable in python that is in outer, but not global, scope?
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Python 3.x has the nonlocal keyword. I think this does what you want, but I'm not sure if you are running python 2 or 3.
The nonlocal statement causes the listed identifiers to refer to
previously bound variables in the nearest enclosing scope. This is
important because the default beha...
How to determine if one array contains all elements of another array
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a = [5, 1, 6, 14, 2, 8]
b = [2, 6, 15]
a - b
=> [5, 1, 14, 8]
b - a
=> [15]
(b - a).empty?
=> false
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How to determine equality for two JavaScript objects?
A strict equality operator will tell you if two object types are equal. However, is there a way to tell if two objects are equal, much like the hash code value in Java?
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BLE（一）概述&工作流程&常见问题 - 创客硬件开发 - 清泛IT社区，...
文章源自：https://www.gandalf.site/2018/11/ble.html
0x1 BLE概述“蓝牙”，即Bluetooth，是斯堪的纳维亚语中 Blåtand / Blåtann 的英化版本。该词是十世纪的一位国王Harald Bluetooth的绰号，相传他将纷争不断的丹麦部落统一为一个王国，并引...
How to use base class's constructors and assignment operator in C++?
I have a class B with a set of constructors and an assignment operator.
5 Answers
5
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Create nice column output in python
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data = [['a', 'b', 'c'], ['aaaaaaaaaa', 'b', 'c'], ['a', 'bbbbbbbbbb', 'c']]
col_width = max(len(word) for row in data for word in row) + 2 # padding
for row in data:
print "".join(word.ljust(col_width) for word in row)
a ...