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Calling filter returns [duplicate]
...urned by the filter function.
If you want a list, just do
list(filter(f, range(2, 25)))
Nonetheless, you can just iterate over this object with a for loop.
for e in filter(f, range(2, 25)):
do_stuff(e)
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Multiprocessing vs Threading Python [duplicate]
...t, niters):
'''
A useless CPU bound function.
'''
for i in range(niters):
result = (result * result * i + 2 * result * i * i + 3) % 10000000
return result
class CpuThread(threading.Thread):
def __init__(self, niters):
super().__init__()
self.niters = ...
surface plots in matplotlib
...
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
x = y = np.arange(-3.0, 3.0, 0.05)
X, Y = np.meshgrid(x, y)
zs = np.array(fun(np.ravel(X), np.ravel(Y)))
Z = zs.reshape(X.shape)
ax.plot_surface(X, Y, Z)
ax.set_xlabel('X Label')
ax.set_ylabel('Y Label')
ax.set_zlabel('Z Label')
plt.s...
What does the slash mean in help() output?
What does the / mean in Python 3.4's help output for range before the closing parenthesis?
3 Answers
...
C++11 range based loop: get item by value or reference to const
Reading some examples of range based loops they suggest two main ways 1, 2, 3, 4
4 Answers
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Is there a numpy builtin to reject outliers from a list
...ing pandas.Series, and replacing MAD with IQR:
def reject_outliers(sr, iq_range=0.5):
pcnt = (1 - iq_range) / 2
qlow, median, qhigh = sr.dropna().quantile([pcnt, 0.50, 1-pcnt])
iqr = qhigh - qlow
return sr[ (sr - median).abs() <= iqr]
For instance, if you set iq_range=0.6, the ...
Initialise a list to a specific length in Python [duplicate]
...ally-empty dict ten times, not ten distinct ones. Rather, use [{} for i in range(10)] or similar constructs, to construct ten separate dicts to make up your list.
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How does zip(*[iter(s)]*n) work in Python?
...e = 3
L = [1,2,3,4,5,6,7,8,9]
# iterate over L in steps of 3
for start in range(0,len(L),chunk_size): # xrange() in 2.x; range() in 3.x
end = start + chunk_size
print L[start:end] # three-item chunks
Following the values of start and end:
[0:3) #[1,2,3]
[3:6) #[4,5,6]
[6:9) #[7,8,9]
...
How do I create a variable number of variables?
...ly create those variable names, and may try something like this:
for i in range(10):
my_calculator.('button_%d' % i) = tkinter.Button(root, text=i)
They soon find that this does not work.
If the program requires arbitrary variable "names," a dictionary is the best choice, as explained in oth...
Scala downwards or decreasing for loop?
...
scala> 10 to 1 by -1
res1: scala.collection.immutable.Range = Range(10, 9, 8, 7, 6, 5, 4, 3, 2, 1)
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