大约有 9,000 项符合查询结果(耗时:0.0437秒) [XML]

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In Python, what is the difference between “.append()” and “+= []”?

...or your case the only difference is performance: append is twice as fast. Python 3.0 (r30:67507, Dec 3 2008, 20:14:27) [MSC v.1500 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> import timeit >>> timeit.Timer('s.append("somethi...
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Duplicate log output when using Python logging module

I am using python logger. The following is my code: 14 Answers 14 ...
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How to construct a set out of list items in python?

I have a list of filenames in python and I would want to construct a set out of all the filenames. 6 Answers ...
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Python: finding an element in a list [duplicate]

What is a good way to find the index of an element in a list in Python? Note that the list may not be sorted. 10 Answers ...
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Iterate over object attributes in python

I have a python object with several attributes and methods. I want to iterate over object attributes. 8 Answers ...
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How to return a value from __init__ in Python?

... Where is new here? Is new implicit in Python? I assumed Python's semantics were different from Java and the other languages that do use this word. – cs95 Jul 20 '16 at 6:06 ...
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Python mock multiple return values

I am using pythons mock.patch and would like to change the return value for each call. Here is the caveat: the function being patched has no inputs, so I can not change the return value based on the input. ...
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What does the restrict keyword mean in C++?

...ed Dec 5 '09 at 17:47 Johan BouléJohan Boulé 1,577
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Create a “with” block on several context managers? [duplicate]

... In Python 2.7 and 3.1 and above, you can write: with A() as X, B() as Y, C() as Z: do_something() This is normally the best method to use, but if you have an unknown-length list of context managers you'll need one of the ...
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Repeat string to certain length

...urn (string_to_expand * ((length/len(string_to_expand))+1))[:length] For python3: def repeat_to_length(string_to_expand, length): return (string_to_expand * (int(length/len(string_to_expand))+1))[:length] share ...